wolfson

I would happily help out in the chemistry and maths field blike.

Nitrogen triiodide, also called ammonium triiodide, is a very unstable explosive that's not really practical due to its tremendous instability and cost. Nitrogen triiodide is formed when iodine atoms displace the hydrogen atoms in ammonia NH3 + I = NI3. Add 2 g of iodine crystals to the beaker, crush them as much as possible with a stirring rod. Add 40 mL ammonium hydroxide to the beaker. After 2 hours the reaction should be complete. Pour the solution over a filter to collect the crystals, any excess can be rinsed out of the beaker with water. Put the crystals where you want them immediately because there only semblance of stability is when wet. Drying will take about 1 hour. You will need a graduated cylinder for measuring liquids. Reference to http://www.roguesci.org/megalomania/explo/nitrogen_triiodide.html I would not do this unless you are a chemist, like myself.

Yes When a wavefront confronts an index step obliquely, one side of the front slows down before the other, thus turning the wavefront. APP(2004)

And doctors may use a transcutaneous pacemaker when a person is asytole, rather than using a defib.

Usually VF is attributed to two main factors, hypoxia and Myocardial infraction there are other cases i.e. serious trauma ect....

Yes ventricular fibrillation basicly means that the chambers of the heart (Ventricles) are contracting very fast thus the heart is not able to produce a beat, during asytole there is 0 output no contractions, and CPR and atropine/adrenaline drugs may restart the heart.

All that was supposed to say is that a defib is not used when a heart has stopped, that is CPR.

Defribillation is used to aguire sinus rhythm, when a person(s) is in V.F or A.F, it can also be used fore a petty palp.

LMAO congratulations Mr.YT good work

The pattern is the following: 1st step: P(1) = 1/2, P(-1) = 1/2 2nd step: P(2)= 1/4, P(0) = 1/4 + 1/4 = 1/2, P(-2) = 1/4 The probability to reach 0 in the 2nd step is equal to the probablity of being at 2 and making a step backward (1/2 * 1/2 = 1/4) and the probability of being at -1 and making a step forward (1/2 * 1/2 = 1/4). 3rd step: P(3) = 1/8, P(1) = 1/8 + 1/4, P(-1) = 1/4 + 1/8, P(-3) = 1/8 The probability of reaching 1 in step 3 is P(3) + P(1) = 1/2 If P(s, n) denotes the probability of accessing point n at step s, then we have: P(s, n) = 1/2 * P(s-1, n-1) + 1/2 * P(s-1, n+1) You must compute the limit of the sum of all P(s, n), where n>=1 (that's what it means to "reach 1"), for s tending to infinity.

Martian atmosphere is incredibly thin compared to ours (about 1% of the Earth's atmosphere) and contains mainly carbon dioxide, this enables the reddish characteristics of the Martian atmosphere to prevail. APP(2003)

The 2000 version.

LOL thought you had siad Isobutane, thats why i was giving: 2 C4H10 + 13 O2 ==> 8 CO2 + 10 H2O Sometimes i really need to read the question.

I was wondering if anyone could tell me how to create a animation, where i can have "blood" trickling down one of my slides. Any help would of course be much appreciated. Thank you

No evidence has been found from animal and human encephalopathies to suggest that milk can transmit the disease.

http://www.corning.com/ophthalmic/discovery_center/ Hope that helps

No need to be like that, ask another maths question and ill answer it for you.

Thus: Ka = 6.5e-5

Thus: Kb = antilog ( - pKb)

Mark, this question is related to tn = ar^n-1, for a geometric progression, you should not "just jeep doubling it", try and use equations to help minimize time.

Salts: Chemical compounds formed by replacing all or part of the hydrogen ions of an acid with metal ions. Acid: A substance that can act as a proton donor. Base: A substance that can act as a proton acceptor.

Hades, oh my, im such a fool, the pKb is the pH of a weak base, im so sorry Hades, and i have a BSc in chemistry how, lol i do appologise use the above it is the correct way, i was still thinking strong base lol.

Ok we will calculate pKb (you are right that Kb is supposed to come intto affect FOR pKb usually in titrtion, so will will calculate pKb for sodium propanoate) Kb= 7.46e-10 (if i can remember correctly) xa = square root of [(7.46e-10) (0.100)] xa = 8.6e-6 M=[OH] xa / Kw = Mb Mb = 8.6e-6 / 1.0e-14 = 8.6e8 Log(Mb) = pKb-pOH pKb = Log(806e8) = 8.93 pKb = 8.93. So we can see that using pKb we therefore have pKb calculated a weak base, is this what you mean, i would actually go with pKb.

nu·cle·ar

Kw = Kb Not at all, Kw is the water constant, as i said in the previous post this is NOT calculating the pKb, we are calculating the pH. Kb = [b:H+][OH-] / Kw = 1.0e-14 (exp)