wolfson

"ordering several high strength Alu", yes Saddam did allegedly order high strength Alu, it would be very good if you revised your thoughts before writing them!!!!!!!!!!!!!!!!!

I would really like a PhD in forensic science, but first of I have to finish my degree then gain a masters then If and only If i have the ability to continue education i shall try my hardest to gain a PhD. Although I have a degree in Chemistry it was the wrong choice, i did well and could have done a master (with trying), but forensic science/crime scene science is the subject that i wish to postgraduate on.

As again if I must repeat there is NO, NONE, NIL evidence that the CIA/SS men/man shot the president!!!!!!!!!!!!!!!!!!!!!!!!!!!!

You should have the Slope constant (or gradient) dy/dx.

Well if you never tried i quess you didnt enjoy the subject, and btw what grade did you get in your Degree a first?

No it depends on how much you try. No trying = Failing.

So the full electronic configuration for Al is 1s2, 2s2, 2p6,3s2,3p1. Just follow the groups along and by the way Al is not a transition metal it is a main group metal.

[Ne].3s2.3p1 is the shorthand electronic congiguration for Al, you use Ne as it is th nearest stable element.

NO IT IS INCORRECT!!!!!!!!!!

NO IT IS INCORRECT!!!!!!!!!!

Electronic confiuration is all about orbital energy, transition elements land on the D block which can contain 10 electrons.

All you ever want to do is create full outer "shells" i.e. look at Na it wants to loose a electron to create a full 1st shell (1st shells are happy (stable) when they have 2 electrons), so the best way would be to create a NaF compounds, as F wants to gain one electron, Al wants to loose 3 electrons so you would bond it to a elemt(s) that wants to gain 3 i.e. N.

If you look at the top of a periodic table the oxidation sates are listed, i.e. F wants to gain one, O two, N three (electrons), and Li wants to loose 1, Be loose 2 B three.

I think the "difficulty of the GRE depends on how clever you are" is not accurate it also depends on how hard you try!!!!!!

Ah but unstable relative to Rn(222).

Fun, well in a nerdy way lol, if you ever need any help just Pm me.

I had already concluded this in previous post. As for the C.I.A. man shooting the pres. the only word that springs to mind is deluded!!!!! (note evidence shows No CIA agent shooting president!!!!)

But still not stable.....

Uranium-238 is an UNSTABLE radioisotope; it decays into Lead-206, a stable chemical element, with thirteen intermediate unstable radioisotopes in between (Uranium-238 decays into Thorium-234, which decays into Protactinium-234, and so on to Lead-206). The reason for the instability is the 6 electrons orbiting the F period (that is suppose to hold 14 electrons). It can be combined with other elements to create a stable COMPOUND, but not a stable Uranium element.

GRE??? I'm asuming A-level, so i would read, Atmoic structure and the periodic table of elements, Ionic compounds, Molecular elements and compounds, Chemical equations and reactions, Stoichiometry and composition, 3 states (not plasma), Soultions, Reaction rates and Equilbrum, Acid-Base Equilibria, Nuclear chemistry and equations, Organic chemistry basics, Basic Bio-chemistry, Nucleic acids, Scientific notation and Significant figures. I hope this hepls you, good studying and best of luck.

Oh and BTW we get those values from your Geometric progression!!!!!!!

Mmmm and when you get to 50, would you like to be gunned down, and anyway dont you think we have short enough lives as it is, without reducing life-span??? And if we have a great leader, and he/she turns 50 we shoot he/she down???

This equation can be manipulated into the form: ln(x)/x = ln(y)/y. This means that x and y are two values that give the same value of the function f(z) = ln(z)/z. If you plot w = f(z) versus z in thezw -plane, you will find a horizontal asymptote is w = 0, and avertical asymptote is z = 0. A horizontal line w = c intersects thiscurve in exactly two points if 0 < c < 1/e, one point (e,1/e) if c = 1/e or c <= 0, and no points if c > 1/e. The z-coordinates of the two points give you the solutions (x,y) where x and y are not equal. If x and y are not equal, then y/x = a will be different from 1. That means that x = y/a, and then: ln(y/a)/(y/a) = ln(y)/y a*[ln(y)-ln(a)] = ln(y) (a-1)*ln(y) = a*ln(a) ln(y) = [a/(a-1)]*ln(a) y = a^[a/(a-1)] x = a^[1/(a-1)] Every solution with x and y unequal does correspond to one of these values of a, namely a = y/x.

Do we know the values of any of these letters yes, there are multiples of different sets so then we can look for a pattern by starting small and working our way up: (x-a)(x-b) = x^2 - ax - bx + ab (x-a)(x-b)(x-c) = x^3 - cx^2 - ax^2 - bx^2 + cax + bcx + abx - abc (x-a)(x-b)(x-c)(x-d) = x^4 - dx^3 - cx^3 - ax^3 + dcx^2 + adx^2 - bx^3 + dbx^2 + cax^2 + bcx^2 + abx^2 - dcax - dbcx - dabx - abcx + dabc See the pattern? For 22 terms the first line would be x^22, and then every combination of 1 letter (26 of them) times x^21 would be subtracted, and then every combination of 2 letters times x^20 would be added, and then every combination of 3 letters times x^19 would be subtracted, and so on and so on until in the last line every combination of 26 letters (1 of them) times x^0 (which is 1) would be added.

Congratulations aommaster, i new you would do well, great scores WTG.