i got 14.8
first i took 90km/h and 140km/h then converted them to m/s which comes out to be 25m/s and 38.9m/s respectively. we will call the car 25,x and car 38.9, z
after this i use the equation
d=Vot+.5at²
where d=distance, Vo=original velocity, a=acceleration, t=time
the first second for car x travels 25m, using d=25(1)+.5(0)(1²) the last part is zeroed out because there is no acceleration. car z travels 38.9m, d=38.9(1). we need to now make two equations involving car x and z that are set equal to each other,but we must also add in those other two answers in them.
since they are going to be at an equal distance in a certain amount of time, we can do this
38.9t+38.9= 25+25t+.5(2)t² (btw we had to add the other values 38.9 and 25 into the equation) now get everything to one side -t²+13.9t+13.9=0
now just put the numbers into the quadratic formula then volia 14.8s
i hoped that help explain, its hard to get these kinds of points across on the net.