DustyMcAwesome

Well what formula can I use for the other 3? I'm very confused.....

Ok, so I determined that Ca(NO3)2 is 164g/mol. So m1=1.00m; v1=?; m2=0.125m; and v2=3l...... Correct?

Molarity=mol/liter... So the equation would be the molarity of the concentrated times the volume of the concentrated is equal to the molarity of the dilute times the volume of the dilute, m1v1=m2v2.

Wait, are you saying to look up the formulas, or the definition of molarity?

M is molarity, correct? We don't use a book, its all oral. I don't remember the forumlas. I think one was m1v1=m2v2...........

Hey everyone, just a small homework assignment, hoping you could lead me in the right direction. :] 1. how would you make 3.00L of a 0.125M solution of Ca(NO3)2? 2. How many grams are in 200 mL of a 1.50 M solution Na2SO4? 3. How much 1.25% KBr solution can be made with 10.0 grams of KBr? 4. How would you make 500 grams of a 0.90% solution of NaCl from a 3.5% stock solution? 5. How would you make 1.00L of a 0.30M solution of KOH from a stock solution of 6.00M? 6. Find the new molarity if 500mL of H20 are added to 200mL of a 2.5M solution of K3PO4? M= Molarity I just need a step in the right direction, like which equation to use. :] Thanks in advance!