hybrid04
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Everything posted by hybrid04
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The question is asking for kilojoules correct? The only thing you have which converts between kj and deg C is the heat capacity. That is how a calorimeter works, you take the known heat capacity of water and based on its temperature change you can determine the amount of heat put into it. Final-inital= change in temperature. Temperature times what gives you joules? Side note: if the answer only asks for kJ the mass of the ammonium nitrate is moot and just there to throw you off. However if they wanted kj/gram ammonium nitrate then you would divide by the mass you added.
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Reading them all never hurt
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If you dont feel like going to google. I dont feel like helping you with such routine information. Google it, then come back. People arent here to do your homework.
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Comparing the geocentional model with the heliocentric model???
hybrid04 replied to openmic's topic in Homework Help
geocentric, earth is center. heliocentric sun is the center. The previous was supported by religions because it allowed heaven to be above earth so you just went up. Heliocentric was supported by many including those such as copernicus and was used to explian certain phenomenon which couldnt be explained in a geocentric system. Perhaps you should show some of your own points and some confusion instead of a blanket wide open question and ask someone to do your homework. -
organic chem 2 inorganic chem physical chemistry 1 some sociology class physics class that discusses teh effects of WMDs on the world
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After browsing some of those links in one of them they claim to have overcome the energy barrier which had previously prevented commercialization of electrolysis. If that is correct it could throw off your calculations woolean.
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I watched that clip and initially i thought it was pretty cool but when i first saw it i wondered how much power it took to run. A few days later this thread has developed and it appears im not the only one to think that. To me it seems like a scam. Id be interested for someone to actually contact them directly and see what they have to say. There is a contact section on their website where they allow you to contact them if you want to see a demonstration of their technology.
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For the first one im assuming you rounded up from 1.6666666 so yes that is correct. The second one is pretty much the same of the first. (.045 mol/L) (1.00L)= # of mol (#of mol) (molar mass)= g solute.
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trig functions translations and combinations of transfomations word problems
hybrid04 replied to Aka's topic in Homework Help
D is the vertical shift and c is the horizontal shift. Since the amplitude is 5 and the lowest level is 11, you just add 5 to that for d. c is the horizontal shift. Remember minus equals right so it would be something like 14 if your scale on the x axis was hours. -
Basically you have to look at the forumulas. Since HNO3 is in excess the amount of product produced is dependant on the other reagent. The mole ratio given from the reaction is 1mol C6H6 produces 1 mol C6H5NO2. Remember it is a mole not a mass ratio. So 1g doesnt make one g. Figure out how many moles of starting material that equals the number of moles of product and then multiply by the molar weight. This gives you 100% yield (or theoretical yield). Multiply that by .71 and you have 71% yield. For the second one im not sure exactly what 'formula units' are but you could still use the same process and get formula units in the end. You need to find the balanced formula for the reaction and then just match the coefficients. 1 for 1 or 1 for 2 etc and then mulitply out the forumla units.
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I drive a hybrid and i love it It has an awesome charge assist gauge that entertains me for hours. It just moves back and fourth....green blue green blue! On a side note it is an excellent car. Granted the getup isnt the most amazing but i didnt get the car to replace something. I got it for the fuel effiency and the money it would save. At current i get about 400 miles to the tank on my 12 gallon tank. Come to think of it thats an understatement considering im to paranoid to let the gauge go that low to even get close to less than 2 gallons. Depending on whether im driving on the expressway, side roads, or stop and go it can drastically effect the mileage. About the last one the hybrid hype. Ive had mine for 2 years. I couldnt be more happy with it. The only downside is the special 0w-20 oil it uses which is expensive to get an oil change at your generic drive up so i have to go to the dealership but they wash my car for free so its all good
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Can sum1 help me figure this Calculus problem out??
hybrid04 replied to Karnage's topic in Homework Help
Im a little rusty on that stuff but i took ap calc in high school and in cases like that my instructor often told us to plug and chug in the calculator. Im assuming you have a TI and you can do a line or expoential regression. Perhaps do that and get a forumla then take teh derivative? (yes the attachment works fine...in both posts) -
reaction of t-butyl alcohol with chromic acid
hybrid04 replied to sheanhung's topic in Organic Chemistry
Or perhaps the alcohol isnt pure? I was browsing wikipedia and stumbled on this Linkie It says its used to test for the presence of primary/secondary alcohols because of that selectivity so perhaps the chromium isnt the problem. -
Check out this Link it has the equation in several forms and some brief explanations.
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I dont see why it would make a difference. Your best guarentee would be to put the units on as to prevent any confusion id say, but im not really speaking from expertise. So just get xx mmHg/ xx mmHg and put in xx kPa/ xx kPa.
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Use dimensional analysis. Take your starting units plus some conversion factor. You'll have to excuse my lack of latex skillz. Just make sure units cancel. For example if you have 100mmHg. (100mmHg) (.133kPa/1mmHg) =13.33 kPa and vice versa. If you start with kPa you divide it by .133 istead of multiply to get the opposite. All you need is the converstion factor and make sure your units properly cancel.
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If you use any major credit card for the purchase you should have no worries about exchange rates. The only problem you might run into is some cards require you enable international purchases. To prevent fraud they are shut off by default. I went to the UK and had to spend 10 minutes on the phone with an amex guy verifying mothers maiden name, SS# etc to buy something for my gf.
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I believe potassium nitrate is found in fertilizer and considering your ordered 8oz of it. No i doubt it. Make and interestig headline though "Sixth Grader Sent to Jail For Buying Chemicals"
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On a more practical note and it depends on your university, but at mine a 2 on the BC exam places you out of the same math class as a 4/5 on the AB exam. If you are taking this to get out of some intro classes in college id definetly go for the BC. Perhaps it might be tougher but depending on where you want to go to school it might be beneficial.
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You also have to consider technique. Very infrequently is the leg extended the whole way when spinning. Usually you spin and then extend at the end. Then you have cm to consider for the person. Generally a useless and impractical thing to consider.
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PhD is a doctorate. Im not sure what the letters stand for exactly. But it is pretty much the highest degree you can hold in the subject and you get to put "Dr." in front of your name. Back on topic i definetly think you should go to college and if you have to take out some loans. There is definetly time to get a job in college and the best part sometimes are jobs on campus which recognize you are a student and are pretty flexible around your schedule. Plus the summers where you just get a good job and work like a grunt. Student loans as someone said soemtimes depend on your family usually it is because as an 18 year old you have no credit so they have no guarentee on the loan which is why one of your parents would have to co-sign. The good side to student loans is they usually can be deferred until you graduate. Time to pay back depends on where you are. In the US it is once you graduate you have to start paying it back, the Brits are different. Your best bet is to research some student loans and try to get the best one for you. Things vary based on the area. You could also start working now while you are in grade 10 and saving up for college because the less you take out saves you money on interest. Just a thought. Also since you dont live in england ignore their system . Sorry but it really doesnt cross over to the us and canada you are to subsidized (and hella more expensive). As far as cost goes it depends on your school and whether you qualify as a home student. I do know in canada they offer some support to home students vs. the US where there is some discount for instate public schools. It can range from 5k-10k/year. If this school is close to where you live depending on how close you can save a huge chunk of change by living at home. On to what you'd like to study difficult i think at the college level really depends on the person and the instructor. I thought calc 2 was a pain in the butt and i hated my instructor but i thought multi variable was easy. Basically you pick it up as you go and just kinda get the feel for what you like. General QM stuff at my school at least you can get right into it first year but most dont till their second. Then hit the real courses after the intro by their third semester. Well now im just rambling anything else i can do feel free to ask
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Well im not quite sure where you went with this P=Fv it may be correct i havent dont one of these problems in a while, but i think that might be the source. W=Fd; You can figure out d based on acceleration and time and F from F=ma. So you have F and d. Power by definition is Work per unit time so you divide W by the given amount of time for P. The way they did it was pretty similar they instead of using d just found final velocity and calculated the kinetic energy then divided it by time for power. It seems to me like you have the general idea just mixed up some definition of terms somewhere. The fact that it is twice that might have to do with the 1/2mv^2 or just pure coincidence. Id just relook at how you defined things and try to understand my methodology and you should be good.
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for the sake of being lazy have you tried http://www.aist.go.jp/RIODB/SDBS/cgi-bin/direct_frame_top.cgi?lang=eng or http://www.sigmaaldrich.com those are pretty useful with most compounds and give sample spectra. In my orgo class i use that as literature comparisons for nmr and ir spectra.
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Types of Enthalpy...and what on earth they mean!
hybrid04 replied to redfox's topic in Organic Chemistry
To be honest i never remember any of those names. All you really need to remember is its natural state is zero. So like O2 is zero (enthalpy of formation) if you go anywhere else it takes some amount of energy. The different "types" are really just some name to describe how you are changing the element/compound. So to go from O2->2O takes some energy to bring it out of its natural state. -
mmm didnt the nazi's use that?