charles langley

As I asked before, how overcomplicated an answer can you get? I have to admit that the standard units had me twisted up in a knot for awhile. but hopefull we will end up with a correct answer to his question. you had posted 3120 Lbf , so I used a potential energy equation as you were talking energy. PE = mgh PE = 4.5359237 kg * 9.807 gc * 3.9624 m = 176.26 j 176.26 joule = 130.002 foot pound for comparison 10 lbf * 13 ft/s = 130 lbf/s thats a large difference from your 3120 Lbf and may be the correct answer to your energy equation. I think that some are considering that the weight scale will read the maximum weight that the mass can possibly supply differently depending on the time involved in stopping the mass. like jumping on your bathroon scales will cause the needle to jump way past your weight. and we would need the time involved to get an exact number here.

force * distance does not solve for force.

I was calculating the acceleration using your 35260N not my 44.45205226 N I was showing the difference between our answers. I dont find that the force is 35,260 N I was refering to the below that you posted Im currious about the above equation , could you elaborate? what is "x" what is "k"

I agree. I had to do something real quick , but when I got back and checked the numbers I realized that the force of 44.45205226 newtons = 9.993218 pound-force so in the 0.8 seconds it really didnt aquire much acceleration at all that would really mean anything. in fact , LOL , it looks like it lost some of the impact. it originally weighed 10 lbs , but by the time all the conversions were done it impacted with less force than it weighs. 0.006782 lbs less.

your right 44.45205226 N = 4.532 847 839 kilogram-force got to go for now though , so have a nice night.

swansont a kilogram-force is the magnitude of the force exerted on one kilogram of mass by a 9.80665 m/s^2 gravitational field http:// http://en.wikipedia.org/wiki/Kilogram-force f=ma physics math , the part of physics we use to determine if the wording of physics is right or not. physics is self checking because of the math , so the math can prove if the words are right or wrong. http:// http://en.wikipedia.org/wiki/Physics

hey , just get a large sphere and cut it in half. put a battery driven toy car inside the sphere. turn the toy on so that the wheels turn. then seal up the two halves of the sphere. its now a closed system. place the sphere on your floor. the toy pushes against the INSIDE of the sphere with a force from the INSIDE ( not external ). you now have a reactionless propulsion device , post it on youtube. any device that does not have a force applied to its outside for propulsion ( external force ) is considered a reactionless propulsion device , and its not supposed to work. the sphere rolls on the floor , because the toy car is providing a INTERNAL FORCE... or as Wikipedia describes it http://en.wikipedia.org/wiki/Reactionless_drive

hey , just get a large sphere and cut it in half. put a battery driven toy car inside the sphere. turn the toy on so that the wheels turn. then seal up the two halves of the sphere. its now a closed system. place the sphere on your floor. the toy pushes against the INSIDE on the sphere. the sphere beging to roll on the floor , because the toy car is providing a INTERNAL FORCE...

Hello swansont a ball with a mass of 4.5359237 kg at a acceleration of 9.8 meters a second / second will fall a distance of 4.9 meters in one FULL second , thats 1 meter further than the ball could fall the 3.9624 meters distance allowed in the question. so the ball travels less than 1 second. in fact it travels for a time of 0.899 seconds its final velocity is 8.8102 m/s and it has a average velocity of 4.4051 m/s durring the .899 seconds the distance the ball travels is its average velocity * time of 0.899 seconds = 3.9601849 meters you are welcome to check my numbers if you like but the 35260N force could accelerate the 4.5359237 kilogram ball to 7773.499 m/s^2 a=f/m = 35260N / 4.5359237 kilograms =7773.499 m/s^2 do you believe me to be wrong? If that were possible I would go buy up every bowling ball I could get my hands on and I wouldnt pay any more electricity biolls , LOL Merged post follows: Consecutive posts merged swansonts how could a 10 lb ball show 98 pounds weight if its just placed on the scale? Im not looking for a argument , I was only trying to help one of the members to solve his problem it seemd as though he never did get a correct answer from those who posted replies to his question. Merged post follows: Consecutive posts merged That is a good and clear explanation of what would "actually" happen.

hello insane alien Im sorry , my first post was a calculation error , Im not sure how I did that but it seemed a good bit too high so I recalculated , and edited my post. he gives the mass and the distance in the question. Mass = 10 pounds = 4.5359237 kilograms Height = 13 feet = 3.9624 meters so its a matter of a = f/m to find the acceleration of 9.8 m/s^2 and F=ma delivers the force. 4.5359237 kilograms * 9.8 m/s^2 = 44.45205226 N and he gave the distance that the ball would travel of 3.9624 meters

Chris I read through this thread and was wondering if you had found the answers you were looking for , so I thought it might be best to just post my findings. F=ma F (44.45205226 N) = M(4.5359237 kg) * A(9.8 m/s^2) the previous post had the answer as follows I couldnt understand the following 35,260 newton = 7,926.763 pound-force which is not hardly a correct answer to your problem. so I wanted to prevent a possible accident in case you were building something. below is a web site that gives several examples to help you learn how to do these calculations , we might just be seeing what you have in a exam. LOL so to avoid a later accident it may be a good idea for you to learn this instead of just being provided with answers. http://www.jupiterscientific.org/sciinfo/examplesfeq.html 44.45205226 kilogram-force = 98.00 pound-force the weight scale would read 98.00 pounds the first time it hits the scale. I suppose that was what you were looking for. here is a good web site to perform conversion also that might come in handy. http://www.onlineconversion.com/force.htm Hope this answers your question.

you should have a look at the following web site. http://technology.arc.nasa.gov/partnering/sbirsttr.cfm