fafalone

But this leads to the question... what if your stick was a cosmic string, which would already have a density of a singularity?

As v -> c, m -> :inf:, so it would collapse into a singularity rather than move superluminally.

Do they even offer QM@usf? i'd be surprised

Powerpoint is easier to use, and there's always the "coolness factor" =)

USF < Community college

Florida bright futures is mad gay. The bastards going to UF get like $8000 or something for full tuition, but I only get $3352 at a private school because I get the "average" full tuition of public school.

I banned myself last night. After blike unbanned me this morning, I removed the limit on number of images per post, so let's try this again. I gave background equations for visualization in 2D first, but I'm skipping that. This isn't nearly in depth, but still has my basic idea. Also realize that I'm a freshman who has self-taught himself everything he knows about QM Begin by using the 3D Hamiltonian operator in the Shrodinger equation: [-h2/2m (:pdif:2/:pdif:x2 + :pdif:2/:pdif:y2 + :pdif:2/:pdif:z2) + V(x,y,z)]:lcpsi:(x,y,z) = E:lcpsi:(x,y,z) H(x,y,z):lcpsi:(x,y,z) = E:lcpsi:(x,y,z) Now use separation of variables: [Hx(x) + Hy(y) + Hz(z)][:lcpsi:x(x) + :lcpsi:y(y) + :lcpsi:z(z)] = (Ex + Ey + Ez)(:lcpsi:x(x) + :lcpsi:y(y) + :lcpsi:z(z)) From this, you should be able to see how working with the wave function in 3 dimensions is just like in 2... you're basically solving the same equation 3 times. Normalization gives: :int::int::int:|:lcpsi:(x,y,z)|2dxdydz = :int:0a(2/a) (sin2((nx:pi:x)/a)dx:int:0b(2/b) (sin2((ny:pi:y)/b)dy:int:0c(2/c) (sin2((nz:pi:z)/c)dz = 1 Hope this helps a little.

I don't believe chaos theory rules out long term prediction of classic mechanical system. If we know what every force is doing, we'd know if it would interact with the object, or interact with something what would then interact... Chaos theory is correct, but only because of quantum uncertainty.

:pi:/6 arccsc(x) = arcsin(1/x) =arcsin(1/2) =:pi:/6

I'm on the 5 hours a night sleep pattern

Yeah, since dx is 1.

Chaos is entropy, entropy is time. On the macroscopic level, there is a limit to which we can predict accuracy; but this limit is where uncertainty on the quantum scale takes effect; so we could predict the weather if somehow we managed to know the position, direction, and momentum of every molecule at the same instant.

Let's look at an example... intg(ln x) u = ln x v = x uv - intg(v du) = lnx*x - intg(x*1/x) = xlnx - intg(1) =xlnx-x take the derivative to prove it: d/dx xlnx-x = lnx+1 - 1 =lnx

For the TCA the intermediates are pyruvate dehydrogenase, citrate synthase, aconitase, isocitrate dehydrogenase, a-ketoglutarate dehydrogenase, succinyl CoA synthase, succinate dehydrogenase, fumarase, and malate dehydrogenase.

Hexokinase, phosphoglucose isomerase, phosphofructokinase, aldoase, dihydroxyacetone phosphate, triose phosphate isomerase, glyceraldehyde phosphate dehydrogenase, phosphoglycerate kinase, phosphoglyceromutase, enolase, pyruvate kinase. In that order. Want the free energy values?

As promised, the steps of glycolysis: We start off obviously with glucose, which is immediately converted to fructose phosphate by the use of one ATP, then phosphorylated again with a second ATP to a compound with the phosphate groups at the C1 and C6 ends of the fructose chain to form Fructose 1,6-bisphosphate. This is split into 2 3 carbon monophosphates called glyceraldehyde 3-phosphate. These are oxidized into acids as NAD+ is reduced to NADH. C1 is phosphorylated to form an acyl phosphate. Now we have 2 1,3-Bisphosphoglycerates. The C1 phosphate groups are then used to phosphorylate 2ADP to produce 2 ATP. Now we have two 3-phosphoglycerates, which react to form two phosphoenol-pyruvates. The phosphate groups are pulled off by ADPs, leaving us with 2 pyruvates for the Krebs cycle.

Just because we don't know the laws to predict the outcome in a quantum system doesn't mean no such laws exist.

Computer isn't random AT ALL.

anyone who consistently misspells genius is no genius

It's not really part of the Krebs cycle, thats why I only had a sentence about it. It's actually another paragraph. There's something like 8 intermediates with O2 at the end.

You asked about both, I'll post all the steps of glycolysis later

Both. ADP (adenosine diphosphate) undergoes non-cyclic phosphorylation via chemiosmosis and the electron transport chain to add another phosphate group (Pi) and becomes ATP (adenosine triphosphate).

Well if you really want some detail... Pyruvate is converted to pryuvate dehydrogenase by HS-CoA, and the free hydogen is used convert NAD+ to NADH, and also produces CO2. Then PyrDH is converted to Acetyl CoA, and then to citrate synthase by way of oxaloacetate, which has a free energy change of -7.5kJ/mol. Then citrate is formed and converted to isocitrate by way of aconitase, which a free evergy change of +1.5. The isocitrate loses a hydrogen to convert another NAD+ to NADH and produce another CO2. Now we have a-ketoglutarate which hydrolyzes succinyl-CoA and in the conversion produces another NADH and CO2 pair. Succinyl-CoA synthase phosphorylizes GDP into GTP and also produces HS-CoA. Now we've got succinate, which becomes succinate dehydrogenase and FAD in converted into FADH2. This leaves us with fumarate, which becomes fumarase after the addition of a water, and then we have malate, which becomes a dehydrogenase as the final NAD in converted into NADH. Electrons from the FADH2 and NADHs are used for ATP production.

Head transplants aren't too far off. A monkey lived a week after one, and that was a few years ago.

Ok I don't know where you got the idea that blike is some sort of genius. No offense, but his intelligence isn't that much above average, and its getting on my nerves