MrWizard

so does that mean it stay the same after dilution? o.O

Alright so I did have all of the equations written quite nicely before but I clicked back and all that time spent typing the equation with the correct subscripts and all, but I realize I don't not really need all the information to understand this step. Basically I am doing a titration lab but I am having problem with dilution: It seems they want me to dilute it twice before titration, Solution X than use Solution X for Solution Y. Solution Y is what will be used for titration. Borax: 3.115x10-3 mol Dilute into a 100ml (0.1L) flask which will become known as Solution X: 3.115x10-2 M Borax Now this following part is where the confusion lyes, I don't know if it is the wording or a miscalculation, this is the procedure: "To acheive the following dilution, transfer some Solution X to a clean beaker. Pipette 10.0mL into a 100mL volumetric flask and make up with distilled water." I know I am supposed to use c1v1=c2v2 but the answer comes out to a factor of 10 higher c1 = 3.115x10-2 M and v1 = 0.01 L ? (10mL of the Pipette) v2 = .1 L (100mL) which makes c2 = 3.115x10-1 M