Aladdin's

Wow- Major thoughts are heading towards travelling That was clearly out of my mind. Actually, I can afford travelling but I don't find it useful to do over the summer - I'm actually not looking for a liesure time to spend. Greece is an awesome place to spend your honey day's ! Regarding working to pay my fees, working is a nice thing to do but I can't stand working if I wasn't a boss. Thanks for the help,apprciated.

I am almost done with my first year at college, and I was wondering what do most college students do in the summer? It is a 4 months long, which is a long period of time. I have thought about entering a gym for sports activities rather than taking the beach and spending all my time with my friends"Like I used to do" - also taking some summer classes that keeps my mind active - reading a book my professor adviced regarding my major is interesting - I'm also also thinking of getting a driving license. Actually, What do most students do during the summer ?

I've calculated that without the use of a calculator. Sorry , it's 13.3

Oh sorry for this error , all units are in the English system. I'll edit my post, thanks.

Two cars face each other on a horizontal road. Car A starts from rest at t=0 amd travels with a constant acceleration of 6ft/s^2, until it reaches a speed of 80ft/s. Afterwards it maintain the same speed.Also after t=50 sec , Car B located 6000 ft down the road is traveling towards A with a constant speed of 60 ft/s. Determine the distance traveled by A when they pass each other. ------------------------------------------------------------------------------------ I was told that for car B we use (t-50) and for car A (t). My work so far : S(A) = 0.5(6)(t^2) +0 +0 S(B) = 6000 + (-60)(t-50) + 0 Set S(A)=S(B) I get two values for t , one is accepted t=45.6sec and the other is rejected(negative sign ). Now if I assume that car A meets car B in the first region, V(A) = 0 + (6)(t) => t=13.5 sec Being 45.6 sec > 13.5 , my assumption is wrong ~ Therefore car A meets car B in the second region (Obvious) S(A) = 0.5(6)(13.5)^2 = 530.67 feet S(B) = 6000 - (60)(13.5 -50) = 8190 feet !! This is impossible , car B is heading towards Car B , so the distance between the two cars must decrease. We've answered a similar question in class , but the difference was that the two cars was launched at the same time .... Thanks for standing by , Regards, Edit: Error in units.

Thanks for the replies ~ I'll do as advised, thanks.

Hi , I need help making lab reports for college,since it's my first year dealing with reports. What I'm asking for , how should it look , it must contain a cover paper as usual as a front page , defining the problem and what are we dealing with , Procedure, apparatatus and some calculation and results. Since there is no samples in my book. I prefer using microsoft word for doing so. Can anyone please share some previous reports he've made. Thanks a lot ..

Hi everyone , I've always wanted to ask this question, regarding chatting. How's your opinion towards chatting , is it a waste of time , or you can achieve some benifets from it , for example : improving your language. Thanks,

Is this similar to the way fire cracks work with musical instruments. By the way nice topic.

Thanks Tony ,

How do you spend your time on the internet ?!

Does anyone knows an educated film , that motivates people to study. The film may describe an action , like the end of a cheater , or sort of that. Thanks

I'm thinking of making a science forum , so what are the steps I should follow for doing this !? I've heard that you must pay money for this , I've also heard that you can steal the design of a website and change text .. !? Well , after surfing the net , there are several free making websites such as yola - - But I think that this must be learnt so it must take time , not minutes !!! Thanks in advance, Regards