alpha2cen

Is the center of the Black Hole no gravity state?

This was the panoramic view of night sky about 1.75billion year ago. At that time, the light, comes from the 2 billion away star, was started about 10.6 billion Universe light year.

If we can see X ray near the beginning of the Universe, the empty area in the Space, itself, will be very clean. High energy beam can not pass through the dust or gas area without loosing energy. http://www.redorbit....chandra-112912/ And, if the measured distance is correct, the empty space clarity will be very high.

These diagrams only show a possibility of existence of a place which is exceeding the speed of light without vanishing. Below diagram is one of the expansion model of the Universe. The speed difference is relative. The value, speed difference / distance, is very small.

This is more detail figure. The coordinate system is changed.

This is a comparing method. $drag \quad coefficient; \quad \eta$ $\eta \propto 2F/AV^{2}$ $1; \quad fish, \quad 2; \quad boat$ $\eta _{1}/\eta _{2}=\frac{F_{1}/(A_{1}V_{1}^{2})}{F_{2}/(A_{2}V_{2}^{2})}$ $F; \quad drag force, \quad V;\quad moving \quad speed$ $A_{1};\quad fish \quad surface \quad area,\quad A_{2};\quad boat\quad surface \quad area \quad contacting\quad with\quad a \quad water.$

The concept is used in the many areas, i.e., design, cad, etc.. Where is the origin not moving in the Universe? So, using the coordinate system to explain it is right, isn't it?

This site tells us the meaning. http://www.toolingu.com/definition-300140-52599-absolute-coordinates.html

This is the case of exceeding the speed of light.

Which part we can see in the Universe at the present ? We can see the limited part of the Universe. The light comes from the near star was passed in the past. And, the light comes from the far away star will be passed in the future. How to estimate that area we can see at the present? We can estimate by using this Figure. In the figure, we are on the AOL(astronomical observer line). Observer line calculation method In the case of constant velocity acceleration. tcurrent =t+L/C tcurrent=t+(Linitial +(1/2)vt)/C where (1/2)v is average velocity value from Big Bang to a point. Solve above equation to the v. v=(2C tcurrent -2Linitial)(1/t) -2C one point expansion Linitial=0 v=(2C tcurrent )(1/t) -2C v; speed of expansion(1x1022km/billion year) C; speed of light(9.46x1021km/billion year) t; time(billion year) tcurrent; current time(13.75 billion year)

What is a problem of this concept? $Mass \quad amount= Field \quad density (field \quad intensity / volume)\times volume( governed \quad by \quad gravity )$

This may seem like adiabatic expansion problem. $dW=-PdV$ $P_{a}V_{a}^{\gamma }=P_{b}V_{b}^{\gamma } \quad ; \quad adiabatic \quad expansion$ $\gamma \quad ; \quad heat \quad capacity \quad ratio$ More calculation is needed.

This is a summary diagram for this topic. Main stream is number 1), i.e., the Universe expansion.

How to drive these relations?

Heat input rate + Heat creation rate = Heat output rate +Heat accumulation rate Heat creation rate = reaction rate of the reaction Heat input rate =0 Reaction rate = Heat output rate + Heat accumulation rate For the reaction heat output rate by conduction is not high, heat accumulation rate in the reactor is increased. So increased reactor temperature induces the reactants or products rapid evaporation. Heat output is mainly established by reactants and products convection. Reducing the reaction rate or increasing conductive heat transfer, by using cooling system, is a key factor to establish the reaction safely. Reactant dilution is one of the methods to reduce the reaction rate.

This is the concept diagram.

$buoyancy-potential=\Delta \rho Vg$ Assuming the temperature on the surface =26.6oC $\Delta \rho =\rho _{273+10}-\rho _{273+26.6}$ $PV=\frac{W}{M}RT$ $R=\frac{PM}{T\rho }$ $\frac{P_{a}}{T_{a}\rho_{a} }=\frac{P_{b}}{T_{b}\rho_{b} }$ 1; at surface, 2; at 3cm above $\rho _{1}=\frac{P_{1}T_{s}\rho _{s}}{P_{s}T_{1}}=\frac{(273K)(29\times 10^{-3}kg/22.4\times 10^{-3}m^{3})}{(273+10)K}$ $\rho _{2}=\frac{P_{2}T_{s}\rho _{s}}{P_{s}T_{2}}=\frac{(273K)(29\times 10^{-3}kg/22.4\times 10^{-3}m^{3})}{(273+26.6)K}$ $\Delta \rho =0.069kg/m^{3}$ $F_{buoyancy}=\Delta \rho V g=(0.069kg/m^{3} )(1m^{2}\times 3\times 10^{-2}m)(9.8m/s^{2})(\frac{N}{kgm/s^{2}})$ $=0.0203N$per surface m2

At the turbine, steam expansion step occurs. So, expansion energy turns the turbine blade. Directly impacting the turbine blade method is Pelton waterwheel method. This method is not used for the steam turbine.

How about this design? Is force balance important at the high speed?

What is the driving force of light moving? Generally, driving force is this kind of formula. d T/dx, dC/dx, dp/dx, etc.

Post #5 dose not mean chimpanzee or gorilla to human blood transfusion. Do not get it wrong.

This is an answer of your question. It is impossible. The reason is explained in this picture. From Bernoulli equation $\frac{P_{1}}{\varrho_{1} }+gz_{1}+\frac{\delta _{1}0^{2}}{2}=\frac{P_{2}}{\varrho_{2} }+g(z_{1}+h)+\frac{\delta _{2}\Delta v^{2}}{2}+friction factor$ $\varrho _{1}\cong \varrho _{2}=\varrho$ $friction factor=0$ $P_{2}=P_{1}-\varrho gh$ ${ \frac{P_{1}}{\varrho }}+{ gz_{1}}={ \frac{P_{1}}{\varrho }}-{ gh}+{ gz_{1}}+{ gh}+\frac{\delta _{2}\Delta v^{2}}{2}$ $\frac{\delta _{2}\Delta v^{2}}{2}=0$ $\Delta v=0$ No fluid moving happen

At first, you decide which experiment you would like to do.

Does chimpanzee have the same blood types as humans them?

This is a diagram of the maximum efficiency of a heat engine. Turbine efficiency can be calculated by using this equation. Efficiency =( Hh - Hturbine, out)/(Hh - Hiso-entropy, out) H; enthalpy