Hi,
I have the same maths question and I am in year 7.
I have the answer to question 2.
The answer is 540.
I chose 1,4,5,27 and multiplied all of them together.
The 1 for the 1 fender
The 4 for the 2 and 4 fender (even numbers are divisible by 2)
The 5 for the 5 and 0 fender (even numbers multiplied by 5 results in a multiple of 10)
The 27 for the 3, 6, 7, 8 and 9 fender
27 multiplied by an even number would result it being divisible by 6 and 18.
The factors of 6 is 3 and 2, the factors of 18 is 3, 3, 2.
I hope it is helpful.
If you could, could you help me with a question?
(Question 3)
Find three 9-fenders less than 1000 with different sets of fenders.
I already have 360, and I could have had 720 and 900 if the question had not asked for the fender sets to be different...
