DimaMazin

I am not against when religious people say that religion is useful , but only when they add that for backward people. Religious people should recognize that science is more important than their religion for humanity. Only then we can cooperate.

Inequality is danger for development of some people already now.

When culture creates rights inequality then our protection should destroy the culture.

Let's consider example when you try to accelerate head first. Head,middle and tail are connected by strong interaction. You,trying to accelerate head, increase distance between the head and the middle. Increase of gap increases strong interaction.Also acceleration increases speed and length contraction, which increase gap too. It creates more strong interaction even between the middle and the head.When the strong interaction force is bigger than acceleration force for the head then the strong interaction force accelerates the middle faster than the head acceleration. The tail accepts sufficient force for acceleration and reducing of distance to the head from bigger force of strong interaction.

I think necessary distance for forces balance is reducing therefore forces of counteraction have different shifts. Counteraction force of tail has blueshift, counteraction force of head has redshift to motion direction.

Even when they are accelerated at the same time then they are initially accelerated to different speeds. Physics should be idealized only by math.

.Agreed. If you have no such material then what proves that all parts of accelerated and contracted object are accelerated at the same time?

Really my math is considering acceleration and speed after one push. Thank you for idea about speed of force propagation. And so speed of force propagation is faster than c . And reducing object reduces speed of force propagation. Maybe therefore my math contradicts GR, but does it contradict QM ?

I confused some things. Speed of force propagation = r/t = r/[(gamma-1)r/(gamma*v)] = gamma*v/(gamma-1)

I didn't say that. Sorry. Seems I have made mistake about propagation at v, I will reconsider it. Do you think all railroad cars in train are simultaneously accelerated after a push?

They are not simultaneously accelerated because forces don't instantly transfer momentum especially when losing length of parts creates delay of subsequent collisions. Therefore speed of force propagation is v.

I consider instant acceleration to v. And my equation is created for it. All parts of object are instantly accelerated to v , but they can't be simultaneously accelerated to have length contraction. Why do you think they are obligated be simultaneously accelerated? Events can be non-simultaneous. You even don't know where is length contracting to.

Agen you make math of break, it is when connection force is weaker than force of acceleration. The forces initially pull tail. If tail is very massive then the forces some pull nose to tail. New math is always wrong for simple folk.

Even when engines are on rocket nose their force with connection force reduce tail length and move the tail earlier than nose. Still I think I do make math of length contraction. You don't make.

Tail, losing own length,approaches to middle. whole length=tail / gamma + length of most of the rocket

The equation is derived from law of length contraction, all data are there . Only moving part of rocket is contracted by gamma factor to motionless part of the rocket. Still middle of the rocket isn't moving therefore it isn't contracted but it is moving to nose as mathematical middle.

With two simultaneously accelerated rockets there is no distance contraction between them when they have weak connection. Your question was about derivation of the math, I showed. What is your next question? Why do you think a tactic of mistakes correction isn't helpful?

Part of distance disappears with any speed and at the speed. In my math is no different between 1 rocket or 2 rockets, because theoretical laws correctly work independently and each with other.The different acceleration is only in time , moving tail is losing length and approaching to the nose, some instant without acting force to the nose(due to losing length) when we consider 1 rocket. I think you don't understand that contracted length of traveler can be created only by two way: with unsimultaneous accelerations or with force of connection when the accelerations try to be simultaneous.

Length of string between the rockets in frameS is r Length of the string in frameS' relative to frameS is r/gamma Contracted distance is r-r/gamma or (gamma-1)r/gamma t=contracted distance/v t=(gamma-1)r/(gamma*v) Sorry. I have mistaken about simultaneity of stops in frameS'. Of course the forward rocket stops later than back rocket in S'. This is single case when the accelerated rockets don't create force to break off or bend the string.

Length of spaceship before motion = r Length of spaceship at v = r/gamma Then time of motion of tail before nose motion=(gamma-1) r / (gamma * v) I have understood this is math of non-simultaneity of instant starts of motions of rockets at v relative to frameS and this is math of simultaneity of stops of the rockets in frameS'.

Events of starts of motions are not simultaneous relative to one of two frames. Why do you think non-simultaneity of starts of motions doesn't cause force between the rockets?

Moving object is moving and contracted in frame S, it is motionless in own frame S'.

I don't see confused me. Our frame is frame S,agen you don't understand that contracted moving objects are in frame S. They don't make necessary math.They didn't make even math of non-simultaneity of start of object motion. Tstart of tail motion=Tstart of head motion -(gamma-1)*length/(gamma*v)

Study this: https://en.wikipedia.org/wiki/Frame_of_reference Moving frame is contracted in our frame and it is in our frame. And at all: show math of contraction of moving object in our frame please. If you don't make the math then you can use my math.

Then all this means that spaceship tail can't be simultaneously accelerated with spaceship nose because it breaks off the spaceship. It additionally works in gravitational fall.