DimaMazin

Point of definition has coordinates (0 ; y) where y =[ 2t*cos(a)*cos(t) - Pi*sin(t)*sin(a)+2a*sin(t)*sin(a)] / [2t*cos(a) - Pi*sin(t)+2a*sin(t)]

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Great diagram. Thanks Taeto. You are the best companion. Now I can see the arc can be defined if it exists. But the solve may be very complex . Therefore it will take a lot of time. There is no prize for such proof . Therefore we should firstly define the arc then maybe some prize will appear. Because it is simpler to define the arc than to prove it exists.

If points of division are dividing the arc and its chord so: left part of the arc / left part of its chord = right part of the arc / right part of its chord then their straight line crosses point of definition.

Division by equidistant points works too because it is proportional(similar) division of the arc and its chord.

Then divide them for 10001000 equal parts. We don't need see it because we can use similar increasing of cathetuses of triangles (they increased are a/2 and chord/2) . I told about them.

Correct. Divide arc for infinite quantity of equal parts and divide its chord for infinite quantity of equal parts. Draw straight line through nearest point of division of the arc to middle of the arc and through nearest point of division of the chord to middle of the chord, Draw straight line though middle point of the arc and middle point of the chord. Point of cross of the lines has coordinates (x ; y}. Instead of first line you can draw next line: draw tangent in point (cos(a/2) ; sin(a/2)), mark length a/2 from point (cos(a/2) ; sin(a/2)) on the tangent and draw straight line through marked point and point (1: 0). Point of cross of new line and second line has coordinates (x ; y). Marked point has coordinates (x1 ; y1) x1 = a*sin(a/2)/2+cos(a/2) y1 = sin2(a/2) - a*sin(a/2)*cos(a/2)/2 Yet we should draw straight line through nearest point of division the arc to edge and nearest point of division of the chord to edge. Then add half of the chord to point (1 ; 0) on straight line of the chord . On edge of the half of chord draw perpendicular to axis OX and mark length a/2 by point with coordinates(x2 ; y2) x2 =( 3 - cos(a))/2 y2 = (a - sin(a))/2 If you draw straight line through points (x2 ; y2) and (1 ; 0) then the line crosses so called second line in point (x ; y). If the arc is the arc of definition then coordinates (x ; y) are the same in both cases.But it is simpler to use equations of the straight lines. Both the lines have point(1;0) therefore in equation y=kx+b b = - k We define k1 for one of the lines and k2 for another of the lines and create equation of the arc of definition: k1 = k2

Yes. There: x = cos(a/2)*(a*cos(a/2) - 2sin(a/2)) / (a - 2sin(a/2)) y = sin(a/2)*(a*cos(a/2) - 2sin(a/2)) / (a - 2sin(a/2))

Therefore shape of circular arc is angle of its segment.

Let's consider arc 2Pi and arc close to zero. Do you think circle and straight line have similar shapes?

Shape of arc is feature of arc, but when we know radius we can use length as shape. 1 rad is complex angle because it has complex ratio to Pi. My formulas show some problems with ratio to Pi .And I don't know will the method solve them or not. If even the arc of definition doesn't define anything, I don't understand why it should be unknown?

If it is correct (1 - cos(a))*sin(a/2)*(2sin(a/2) - a*cos(a/2)) / [(a - sin(a))*(a*sin(a/2)+2cos(a/2) - 2)] = 1 Then you can check your angle. Coordinates of definition point: x = cos(a/2)*(a*cos(a/2) - 2sin(a/2)) / (2sin(a/2) - a) y = sin(a/2)*(a*cos(a/2) - 2sin(a/2)) / (2sin(a/2) - a) I don't know but maybe the method will help to define exact value of Pi .

Seems that is wrong. I should remake it.

Compare North Korea and USA.

Everything is ineffective in socialism therefore military development is the most important.

Rather the arc(angle) is very complex and its sine and cosine are more complex, only therefore we can not use this method for definition of trigonometric functions.

Yes. If you know what is arcsine and arccosine then you should understand what is arc of unit circle. Arc of definition is part of unit circle.

Coordinates of point of definition: x = ( a - sin(a))*cos(a/2) / [cos(a/2)*(a - sin(a)) - sin(a/2)*(1 - cos(a))] y = sin(a/2)*(a - sin(a)) / [cos(a/2)*(a - sin(a)) - sin(a/2)*(1 - cos(a))] Pi/(2a) = sin(a/2)*(a - sin(a)+1 - cos(a))/[sin(a)*cos(a/2)*(a - sin(a))+(1 - cos(a))*((sin(a/2) - cos(a/2)*(a - sin(a))+sin(a/2)(1 - cos(a)))]

Excuse me Studiot. I just showed how it can define unknown angle when arc of definition is known and coordinates of point of definition are known. But if your computer can solve very complex equation then please solve this one: a is arc of definition ( rad) Pi/(2a) = sin(a/2)*(a - sin(a)+1 - cos(a))/[sin(a)*cos(a/2)*(a - sin(a))+(1 - cos(a))*((sin(a/2) - cos(a/2)*(a - sin(a))+sin(a/2)(1 - cos(a))]

Sine is known there. I defined angle.

Length of arc of definition is a coordinates of point of definition(cross point of 5 lines) are (x1 ; y1) Length of chord is 2sin(a/2) Equation of chord is y=(sin(a)*x - sin(a))/(cos(a) - 1) For example we know sin and cos of unknown angle Let's define unknown angle : coordinates of point of unknown angle on arc are (cos;sin) Then draw straight line through points (cos;sin) and (x1;y1) Equation of the line is: y=(y1 - sin)*x/(x1 - cos)+sin - (y1 - sin)*cos/(x1 - cos) Cross point of the line and chord has coordinates (x ' ; y' ) We know equations of the line and the chord therefore we can define x' (it is complex) (1 - x')/(1 - cos(a))= part of divided chord / chord = unknown angle / a unknown angle = a*(1 - x')/(1 - cos(a))

Yes and proportional divisions can be any , but coordinates of cross point should be constant.

Draw unit circle x2+y2=1 Mark angle 166 degrees or 168 degrees . Divide this angle for 6 equal parts. Draw chord of this arc(angle). Divide the chord for 6 equal parts. Draw straight line through 2 points , one of which divides arc for 1/6 part and 5/6 parts, another divides chord for 1/6 part and 5/6 parts. Then draw second straight line through 2 next points, one of which divides arc for 2/6 and 4/6 parts, another divides chord for 2/6 and 4/6 parts. Draw next straight lines through corresponding next points. If your arc is arc of definition then all these straight lines cross in one point of definition trigonometric functions and angles. If you know angle then you can define sine&cosine. If you know sine&cosine then you can define angle because you know coordinates of point of cross straight lines .

Arc is angle(rad). I made some explore. If it exists then rather it is between 5/6 Pi and 17/18 Pi .

I should not louse time. I should define arc of definition.