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hypervalent_iodine

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Everything posted by hypervalent_iodine

  1. I'm not sure why you're so hesitant about ether? As long as you're not lighting fires near it and you're working in a fume hood, you won't have a problem with the flammability. Unless you have some really compelling reason not to use ether, I would just stick with that.
  2. ! Moderator Note If you take issue with a moderator action, even if it is 7 months old, please feel free to report it or PM a member of staff. Do not derail this topic any further.
  3. Everything is pain.

    1. Show previous comments  17 more
    2. fresh

      fresh

      why everything is pain ? hypervalent_iodine, you are such an outstanding girl !

    3. hypervalent_iodine

      hypervalent_iodine

      fresh: at the time that I wrote this, I was feeling very sick and sorry for myself. I'd like to say I'm all better now, but as it happens, I came down with another nasty bug just yesterday.

    4. fresh

      fresh

      Although I know little about you, I admire you. Being a learned young girl,you have nothing to worry about.

  4. ! Moderator Note BTW, the stuff about the BB, evolution and abiogenesis are off topic. If you wish to discuss them, we have plenty of threads on the matter or, you could start your own. It would be appreciated if other members did not respond to that part of Greylorn's comment, also.
  5. ! Moderator Note Moved to speculations.
  6. Nope. You need to do a few conversions first and you need to know that the molar mass of H2 is ~2 g/mol, not 1 g/mol. It is also useful / necessary for you to recognise that 298 cc is another way of expressing mL (so volume, not mass) and STP is an acronym for standard temperature and pressure (i.e. 298K, 1atm). For the purposes of this question, you can assume hydrogen to be an ideal gas, in which case there is a simple rule of thumb for how many litres a mole of gas will occupy at STP. It shouldn't be too hard to look up. Also, moles =/= mass. You do not have 1 mole of Mg, you have 1 gram.
  7. Are you familiar with the concept of moles? You may want to look this up if not. Your equation: Mg(s) + H2SO4(aq) --> MgSO4(aq) + H2(g) Is essentially telling you that for every mole of Mg metal that reacts, you will produce 1 mole of H2 gas. You should be able to use that information to solve your problem.
  8. I don't know terribly much about relativity myself, but I assume that the reason so many different people claim it to be false for so many different reasons because so many different people don't really understand what's going on (but think they do). The theory of evolution suffers from much the same problem.
  9. ! Moderator Note krash, you've been warned before about the attitude you display in your posts. We do not permit members to attack others in this forum. You are welcome to attack ideas, but criticizing the person making them is not acceptable. It would also be advisable for you to make some sense and cut the vague conspiracy nonsense (in other words, stick to the topic). If you wish to talk about your speculations, we have a forum for that.
  10. That's because what you're talking about are esters (-COOR), not carboxylic acids (-COOH).
  11. I think it dissolves it to a very, very minor extent. Of course, the best way to find out failing reliable data searches would be to try and dissolve some, filter off the solution and see how much NaCl you have left or evaoprate the DCM and see how much NaCl was dissolved (the latter might be easier).
  12. ! Moderator Note I haven't read all of the replies since swansont's last modnote, but I think it's fair to say that almost everyone in this thread has pretty much ignored it. I do not think it is fair to close someone else's thread because a few people do not know how to follow forum rules or listen to staff warnings, so instead I am moving all of the OT posts to the trash. In future, they will be deleted and the next person who derails this thread will be getting an official warning.
  13. Our filter normally catches most of them, but we're having a little trouble with it at the moment for some reason. Supposedly this is the new and improved version. Cap'n is or will be looking into it, at any rate.
  14. Only if it is relevant to your post and only if it is there for supporting information rather than as the whole body of the post. Basically, don't advertise your book. This is after all a discussion forum.
  15. ! Moderator Note Greylorn, After reading a few of your posts, I think it's perhaps time staff remind you that this forum is not the place to advertise your book.
  16. ! Moderator Note Dbaiba, To further elaborate on my other modnote, a number of your more recent comments contain offensive statements and are in violation of our forum rules. If you cannot abide by these rules, which you agreed you would do upon signing up, you will be suspended. Comment on the ideas, not the people making them.
  17. ! Moderator Note Moontanman and Dbaiba, Stop derailing this thread. I have, once again, split the posts about the Qu'ran into the thread the belong. Also, Dbaiba, calling someone ignorant and mallicious is indeed an offensive statement. This is not up for discussion in this thread. If you have an issue with it, report it or PM a member of staff. Further replies to modnotes in-thread will be removed.
  18. ! Moderator Note Staff have decided to reopen this thread. However, the antagonizing jabs at one another are to stop. This goes for all parties equally.
  19. Don't worry so much about the water component of the KOH. It's really only the % by mass of KOH that you need to worry about. If it helps, another way of expressing the amount of KOH you have is by saying that in every gram of your impure sample, you have 0.84 grams of KOH. If you know the mass required to make 1.2 L of 0.60 M KOH, then knowing how much of the impure stuff you need is just a simple conversion. For instance, if say I need 0.84 g of KOH to make up my solution, then I would need 1 g of the impure sample. If I need 1.68 g of KOH, I would use 2 g of the impure sample (1.68 / 0.84 = 2). Your first step is, as studiot said, to work out the mass of KOH required to make your solution.
  20. In either case, telling you the answer won't help you. What exactly are you struggling with in answering the question?
  21. Since this is a homework question, we can't simply give you the answer, so what do you think?
  22. ! Moderator Note Since you all seem to have a problem in comprehending very simple requests in big red boxes, I am going to close this pending staff review.
  23. Basically, what Ed said. Your funds are no where near enough for a lab. The glassware wouldn't be too expensive, but you will certainly not have enough to install engineering controls, equipment such as vacuum pumps or purchase chemicals (you wouldn't even be able to afford one of those aspects, really). What exactly are you planning to use the lab for?
  24. ! Moderator Note That is not how this works. You use this forum to discuss or you don't use this forum at all. I will close this thread if it keeps up in your next post.
  25. ! Moderator Note Enough of the hostility. Seriously, it's like moderating a kindergarten here lately. Play nice.
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