HelloHelp100

Last Question, this is my consensus, please help: After doing extensive research, where we mixed potassium chlorate and sugar and then added sulfuric acid to produce a purple fire. So far we used the equation 2KClO3(s) —heat—> 2KCl(s) + 3O2(g) and said the sugar was a catalyst in the sense that it was used as a fuel to accelerate the combustion reaction. Also, we said that other fuels could replace sugar and the reaction would be the same, and sugar is just easy to use, so it does not need to be mentioned in the equation; and sulfuric acid was just a spectator. Therefore, this equation shows only the decomposition of potassium chlorate. Some sources agreed with this, but others disagreed. Other sources have used C12H22O11(s) + 8KClO3(s) --heat--> 12CO2(g) + 11H2O(g) + 8KCl(s) + 2029 kJ as the actual reaction, and said sugar was not a catalyst but a necessary reactant. Are we correct? Is sugar a catalyst?

Remember me, "Hey, me and a friend did the instant chemical fire experiment. In this experiment, you combine safe amounts( 3-4 grams) of each potassium chlorate and granulated sugar and add a couple drops of sulfuric acid. The first two times we did it, we did it in a beaker under a fume hood. However, a very small flame occured. the next two times we did it, we did it on a watch glass and we watched a wild purple fire" This is the equation: 2KClO3(s) —heat—> 2KCl(s) + 3O2(g) , sulfuric acid is a spectator, and sugar is a catalyst in the form of energy so they do not appear in the chemical equation. I have a couple more questions: 1. Why was their white smoke? Carbon was not apart of either the reactants or the products. 2. What were the black left overs? Was it burnt KCl, because that is what KClO3 decomposes into. Were they sugar or potassium chlorate. Both were originally white. 3. A combustion reaction took place, because there was a fire. however, the above reaction accounts for only what happened to the Potassium Chlorate. Why did O2 escape from that? 4. Are their any alternate chemicals that could have been used to produce the exact same reaction? I think maganese catalysts work, and Rb and Cs instead of K would work because they produce similar wavelengths which would make a purple fire. Is this correct? 5. It is true that sugar is a catalyst for the reaction in the sense that it provided energy and accelerated the reaction, correct? 6. The above accounts only for the decomposition of potassium chlorate with heat and a catalyst. However, what are the other byproducts that occur but are not apart of the chemical equation, like CO2 and H2O? Why can't I put them in the chemical equation.

at what temperature does glass break?

no it is not hw, can you at least give me a direction for discovering possible reasons why the reactions different. I thought of this by myself, were they possibly different because of limited surface areas in the beakers which would constrain oxidation?

Hey, me and a friend did the instant chemical fire experiment. In this experiment, you combine safe amounts( 3-4 grams) of each potassium chlorate and granulated sugar and add a couple drops of sulfuric acid. The first two times we did it, we did it in a beaker under a fume hood. However, a very small flame occured. the next two times we did it, we did it on a watch glass and we watched a wild purple fire 1. Why did that happen? Is this due to surface area in any way, and how it impacts oxidation. Could you answer and reference a website that answers it too? 2. Why was the flame purple, this really confused me? 3. what would be the chemical equation for this reaction, and why did would it form such products? KClO3 + H2SO4 + C6H12O6-->KClO4 + CO2 + H2. Would this be lost? It is kind of complex. Thanks, this has been bugging me for a long time, and I couldnt' find a website that would answer this, I think this is pretty simple stuff. Please help. Thanks!