are you kidding lol? i didnt think either of my answers were even close to being right but the way i did it was:
50,000 x 5 = 250,000 (momentum of submarine)
100 x 10 = 1000 (mementum of torpedo)
250,000-1000=249,000
249,000/50,000=4.98 m/s
then for the torpedo i did:
7/9(10)+5=12.78
7/9 was there because there is 180 degrees that the torpedo could be launched. However 0-90 degrees and 90-180 degrees mimic the same effects on the velocitity of the torpedo. Therefore since the torpedo was facing 20 degrees up or down the velocity of the submarine would only be about 7/9 effective. I then added 5 for the original difference between the submarine's velocity and the torpedo's.
..I gotta learn how to right my work down when I do it, I had to redo the problem to find my work.