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Mandy :)

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  1. Mandy :)

    probability

    In humans, the ability to taste PTC is dominant over non-tasting. Two heterozygous tasters have three children. What is the probability that one or more of the children will be non-tasters? a. 0.684 b. 0.578 c. 0.251 d. 0.422 e. 0.004 I assumed that the two heterozygous parents would have a 1/4 chance of passing on the recessive, non-tasting gene, aa. With three children, I would think to use the product rule, thus multiplying (1/4)(1/4)(1/4)= 1/64 = 0.0156 Please help explain what I have done wrong. Thank you.
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