mdgurl07

now wat do i do is that even correct?

k lets see i did this: H2SO4 + 2 KOH -> K2SO4 + 2 H20 (0.861g of KOH)(1 MOL koh/112.2114g KOH)(1 mol H2SO4/2 mol KOH)=3.8 x 10^-3 mol H2SO4

oh k well lets see if i can do that much thanks a bunch!

i have this problem and idk what to do? can someone plz help me.... --> A 36.0 mL sample of aqueous sulfuric acid was titrated with 0.250 molar KOH(aq) until the chemical indicator signaled that the solution was exactly neutralized. The mixture was then carefully evaporated to dryness, then the residue was dried in a drying oven. The residue was then weighed and a value of 861 mg was obtained for its mass. Calculate a value for the quantity of the potassium hydroxide solution that was used in the titration from this data.