bloodhound

how come new york has that stuff? i thought england should have the originals. jakiri: unfortunately this is not a eintstein vs newton vs liebniz thread

i forgot the add that the integral is with respect to x.... anyway this is how you do it you find M easily giving its value 2. then u have to find [math]\int \int_{A}y dA[/math] where A is the area bounded by the sin curve between 0 and pi and the horizontal axis. writing that as interated integral you get [math]\int_{0}^{\pi} \int_{0}^{\sin(x)}y dy dx[/math] [math]=\int_{0}^{\pi}[\frac{y^2}{2}]_{0}^{\sin(x)} dx[/math] [math]=\frac{1}{2}\int_{0}^{\pi}\sin^2(x) dx[/math] [math]=\frac{1}{2}\frac{\pi}{2}[/math] dividing by M u get . [math]\bar{y}=\frac{\pi}{8}[/math] actually there is the constant density function in both the M integral and the above one... but since they are constants, you can take them out the integral in both of them and they will just cancel out.

but of course i did it by hand... in the above simplified formula the the bounds in the integral only works for this example!! dont go using it for other laminas as well. the general formula is the same except you have to sort out the limits.

if the density function is constant then the formula can be simplified to [math]\bar{y}=\frac{\frac{1}{2}\int_{0}^{\pi}y^2}{M}[/math] where M is just the area under the curve

well i just computed it.. i got the [math]\bar{y}=\frac{\pi}{8}[/math]

http://mathworld.wolfram.com/GeometricCentroid.html just take the density fucntion to be constant. i remember doing this is my mechanics a level. and i remember not having anything to do with double integrals... but have a go anyway

well i can't remember the formula.. just find the formula for the centre of mass for a lamina.

hmm... i still dont know what a sinus is.. the centre of mass will lie on the line of symmetry. if u know one condition on the position of centre of mass , and u know the line of symmetry , then u should know the point itself.

news is that suprnova staff are now concentrating on a decentralised bittorrent protocol. so that there is no need to rely on a central tracker. its called Exeem. look it up on google. not much info is isohunt still on? last time i heard they shut down voluntarerely.

whats a half sinus period?

pirate bay and bi torrent is all good. for specific stuff like anime, there are plenty of trackers out there.

dont know about einstien proving newton wrong, i would rephrase that as "newtons being a specific case of einsteins" or "eintein expanded newton"

http://story.news.yahoo.com/news?tmpl=story2&u=/ap/20041228/ap_on_re_as/quake_tidal_wave death toll rises to 40,000

they were from two different eras, comparision doesnt make ssense... but what the heck... i'd go with newton... cos he develped the important part of maths known as calculus and he did other stuff, which einstein cannot touch.

ur paranoid about security dude. with all those checks.

i am not doing it now, but ill be starting once my exams are over in january

i would just take chunks of water. and define the chunk as one object

somehow , i doubt doron knows what a mapping is.... i gave the same example before as well. but doron refuses to acknowledge that its a mapping between infinite sets. either his definition of a map is completely different from ours, or he doesnt know what he is talking about. if its the first, could u lets us know what u mean by a map

i never read ezines and blog anyway.. i dont know what purpose they serve

right now i would just use the 1/2 mv ^2 .... after i do my fluid mechanics module next semester i might know better

sky news reporting upto 23,500 dead

i think it would be preferable using LATEX. This is what i get from banging in equation in Maple [math]\exp[{\frac{\mbox{LambertW}(\ln(a)a^{a+1})}{a^{a+1}}][/math] to dimshadow. maple gives this [math]\frac{\ln(a)}{(a+1)\mbox{LambertW}(\frac{ln(a)}{a+1})}[/math] i dont know LW function personally, but u can have a read about it at http://mathworld.wolfram.com/LambertW-Function.html

yes thats the whole point. evaluating that formular at infinity doesnt make sense. the best you can do is take a very large number which is give u a very good approximation to pi.

this is old news. i "would" post some really good suprnova alternatives, but i have to ask the mods if its allowed.

infinity -2.. or pi/infinity makes no sense, as those binary operations involving "infinity" is undefined. you could however circumsribe the circle with a polygon outside and inside the circle... then take the infimum of all the polygons outside the circle and supremum of all the polygons inside the circle and if those two value correspond, then thats the value of the area of the circle... thats just the basic principle of reimann integration.. where u basically take step functions above and below the function