bloodhound

isnt that a bit wrong? i mean if the acceleration to 5 mach is slow enough. i am sure the pilot will survive. and as long as he doesnt pull any manuevers (ie just travel in a straight line) he should be alrite. I mean we on earth DO travel quite fast.

test [math]x^2[/math] edit: it works for me! try pressing ctrl + f5

also: if u have an old pc like PIII 300MHz then you can turn it into a firewall by installing a firewall OS. can't remember the names. i think IPcop was one of them

I mean Newtons work is just unimaginable... to claim that two masses will have a force between them because they just do is mindboggling.

Another useful test in factorising polynomials over rationals, or to test if it has any rational roots would be the Rational Root Test

well u know there is 1 real root, so there must be another real root, and then two complex roots which are conjugates. here is my screenshot from maple

jakiri i dont understand your last sentence, could u explain in more detail.

well do it this way. [math]x^{2}(x-1)-\frac{2}{x}=0[/math] [math]x^{3}-x^{2}=\frac{2}{x}[/math] [math]x^{4}-x^{3}-2=0[/math] then -1 iby inspection is a root, therefore (x+1) is a factor of f(x). then you can reduce the polynomial into a quintic information on solving quartic http://mathworld.wolfram.com/QuarticEquation.html there is also a link at the bottom to solutions to quintic I banged the equation into Maple, and the solutions are horrible. the only nice solutions is -1, the others are massive strings of numbers.

solve what? i assume u mean finding the root of that function it looks like u will need to find the roots of a quartic of a form ax^4 + bx^3 + c = 0 there should be a general formula for that, i dont know it. lemme just try to look for it on the net

i thought malaria was curable

hi to all the new members

well, i always had a flair with maths, so thats that.

there are inbuilt utilities that allow u can setup web servers and ftp servers in xp prof. while in home u will have to install third party stuff lik apache etc.

i heard that the blonde gene is sweden is gradually dying out as well. (according to some random documentary)

i thought SATA was the fastest.

well obviously the easiest way to approximate the are is to fill the circle with tiny squares

just doing a phd will give you the doctorate.

that cos ur using a uni with its sub unit... 1' is definitely half of 2'.

i would have thought , the metabolsim would have slowed down as well due to the time dilation ( from the point of view of the earthbound bro)

oh yeah. i remember why its 2^n -1. the number of subsets of a finite set is 2^n, cos you have 2 option for each element ( ie to include or not to include). and the -1 is there because we do not want the empty set to be counted as well.

i sorted it out. here [math]\binom{n}{i}=\frac{n!}{i!(n-i)!}[/math] and then u sum that from i = 1 to n example. n = 3 so [math]f(3)=\sum_{i=1}^{3} \binom{3}{i}[/math] [math]=\binom{3}{1} + \binom{3}{2} + \binom {3}{3}[/math] [math]=\frac{3!}{1!2!} + \frac{3!}{2!1!} + \frac{3!}{3!0!}[/math] [math]=3+3+1[/math] [math]=7[/math] here [math]n!=n(n-1)(n-2)...(2)(1)[/math] and [math]0!=1[/math]

an alternative formula would be if you have n objects, then [math]f(n)=\sum_{i=1}^{n} \binom{n}{i}[/math] will give u the number of arrangements as described in your previous post. you can work the 2^n -1 answer from scracth. its basically to do with two choices for each object in the collection. so you either include x, or don't. so for n objects you have the term 2^n -1 possible outcomes. i cannot seem to remember where the -1 comes in . i think its due to that fact that once you get to the nth item , you cannot choose to not include it (as if u choose not to include everything , you get the empty set)

well if u take the domain to be just the non negative integers, then f(x)=2^x-1 is probably the only function passing through those points. if u take the domain to be R, then you define the function to be f(x)=2^x -1 if x=0,1,2,3,... and then you can let the function do anything in between the points. for example f(x)=0 for [math]x \in \mathbb{R}-\{0,1,2,3,...\}[/math] but in ur case it looks the domain is [math]\mathbb{N}[/math]

you haven't defined your source and target for the function. there are infinite numbers of functions [math]f \colon \mathbb{R} \to \mathbb{R}[/math] passing through those points.

many universes as in multiple universes? or parallel universes? i have read in some book that there may be quite a lot of universes connected by black holes ( and white holes on the other side)