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MigL

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Everything posted by MigL

  1. Its not cosmology and particle physics that have stepped off the 'deep end'. It is people, like you, who don't have a very clear understanding of cosmological theory, that are acting like the sky is falling. It is NOT a finite amount of substance expanding into an unbounded volume. That is not part of any viable big bang model. I suggest you do some reading and inform yourself. Or ask certain members of this forum, a lot of them are willing to explain the details of cosmological theory to you, as long as you don't come with a lot of pre-conceived notions.
  2. Draw a picture to scale and see just how much the moon's face is shielded by the earth. The angle to the target is a full 180 deg. minus the angle shielded by the earth. Most interplanetary debris is in the plane of the ecliptic, so that should be a good approximation.
  3. Could be atomic. Degenerate just means ( in the case of white dwarfs ) that all lowest electron energy states are full and any further compression would violate Pauli's exclusion principle. Neutron degeneracy ( as in neutron stars ) would lose any semblance of atomicity since it would be composed mainly of neutrons, the electrons having been forced from their lowest energy states into the nucleus to combine with protons.
  4. I believe regular uranium 238 is a neutron moderator and so any naturally occurring uranium on the earth or outer space ( meteorite ) would tend to suppress fission reactions. It is only enriched uranium 235 which supports and amplifies fission reactions. Weapons grade is, I believe 98% enriched, but that takes multiple stages of centrifuging and filtering uranium fluoride gas. Haven't looked this up in a while so my numbers may be wrong.
  5. Look Lala, your own post state that it is charged particles that make up the solar wind, which are affec.ted by the earth's magnetic field ( north/south magnetic poles ), not light. Everyone else is being too polite to tell you, but can you read and understand your own posts ??? Get a clue before you get an opinion ( and an attitude too ).
  6. Well Owl, let me try to explain along the same lines as the other posts on this topic. Your 'now' is the apex of a past light cone which extends doownward into the two bottom quadrants of a distance time graph. The slopes of the light cone are +/-186000 where the distance is in miles and the time is in seconds. At your 'now', the apx of the cone, the sun is outside your observable universe and will not enter it until the light cone passes through the distance of 93000000 miles which is in about 8 min. I don't know what being outside the observable universe means to you, but that sun will never have any effect on us in any way. We can only ever perceive the sun of 8 min ago. Oh, and don't let DrR catch you voicing your 'universal now' philosophy, or he'll be all over you again.
  7. When discussing modern physical concepts, check your 'common sense' at the door. There is no 'common sense' in Quantum mechanics or General relativity. Common implies low speed, low energy and large size/distance. That solar flare which according to you is 'happening now', has absolutely no way of manifesting itself to us in the global now, because the global now does not exist. You can define it as 'happening now' all you want, but you have no way of ever detecting it or its effects for 8 min.
  8. As DrR has stated several times, a large, galactic centre sized (>1000000 solar masses ) black hole would have very weak tidal ( differential gravity ) forces until well inside the event horizon. You wouldn't notice any difference upon crossing the event horizon until much later. A very small black hole or, for that matter even a neutron star, would have severe tidal forces ( even outside the event horizon of the small black hole ).
  9. Ahh, but you did just go philosophical. You still cling to the unscientific concept of a global now. It is not just images that are conveyed at the speed of light, but all information. For all intents and purposes, the sun IS ( to us ) as we see it, not 8 minutes earlier. The only way to make ours and the sun's "now" somewhat coincide, is to move very close to it so that a loosely defined local now can apply to both.
  10. The primordial fast-burning star which gave rise to 'our' heavy elements was formed at a time when hydrogen clouds were more abundant and vast than they are today, much like the difference between outer spiral arms and central regions. I believe it is the nova/supernova shock wave which causes the compression waves in surrounding interstellar gas clouds, and is the cause of the initial 'seeding' of new stars, before gravity completes the task.
  11. Well atmospheric drag was my thinking also but the Roche limit given by D.H. is well beyond the atmosphere. I still don't uderstand why the rings of Saturn have such a well defined inner and outer orbit. They are attributed to a fragmenting satellite, but their density is almost constant from inner to outer circumference, with none of the decrease in density and straggler particles you would expect from a chaotic event, almost as if they had been swept clean by some effect.
  12. I'm sure DrR is just trying to get you going by being very picky with the definition of solution. I'm sure he's more familiar than most with perturbation and approximate methods. There may be no exact solution to many body problems, but given enough computer time, you can get as close ( decimal places ) as you wish. I, myself have not done any >2 body gravitational approximations. But I'm sure anyone who'se studied physics will have solved the Helium atom using these methods. At the time I was in school we used Hollerith punch cards and programmed in Fortran IV. Several hours later you'd have your stack of fanfold results which then needed debugging. Ah, the convenience of modern computers.
  13. Appreciate your imput Janus. I guess if you are also of the opinion that none of the disintgrating moon's pieces will impact the Earth, then my thinking must be at fault and I obviously need to re-examine the situation.
  14. I know that a lower orbital speed will usually just drop you down into a lower orbit. But did you miss the part in the OP where the moon has moved a LOT closer to the earth and is torn apart by tidal forces ( wouldn;t be a day in the park for the earth either ) ? Do you know at what distance this would happen ? I don't. But I base my reasoning on observation of similar situations. Have you seen pictures of Saturn's rings ? Have you ever wondered why there are no 'stragglers' below or above some very clearly defined orbits ? Does your book on orbital mechanics explain that ? Maybe my choice of words was wrong and I shouldn't have used unstable. But pick up a rock and throw it. It is now in an orbit. Unfortunately its orbit passes through the earth, ie IT HITS THE GROUND !
  15. At no time did I mention circular orbits. But if you know your Kepler as you say, then you know that for any orbit there is a well defined orbital speed associated with the distance, whether we are talking circular elliptic or even parabolic orbits. Deviations from this relationship makes for unstable, ie not sustainable, orbits. Or was Newton wrong ?
  16. Uncertainty is an inherent property of quantum reality. The measurement problem is used to explain the situation because most people find it very hard to believe reality is so strange. Go back and re-read some of the excellent guidance you've been given in previous posts. Oh, and a very good authority says 'The Grand Design' is a sell-out and not up to the standard of his previous books ( I haven't read it yet myself ), and you'd be better served by the Feynman lecture series ( which I have read and are excellent ).
  17. Last time I checked, a decaying orbit is a spiral. The moon's centre of gravity is in a somewhat stable orbit at a given orbital speed. If you break apart the moon such that there is little cohesion between the pieces, then the close face fragments are closer by a moon radius than the centre of mass, but are not orbiting any faster than the centre of mass, By Newton's law then, those pieces are in a less stable orbit will experience a decaying orbit.
  18. I would say that the 'change in geometry of spacetime' is not 'the source of gravitational force', rather the geometry of spacetime IS gravity, which then influences the 'motion of objects'. I believe that's the question you asked. The rubber sheet analogy does work, as long as you remember that its basically a 2d representation. Most shopping malls have funnel like devices ( intended to collect money for charities ) where a child can pitch in a coin, and it will slowly spiral down into the collector. If there was no friction between coin and funnel/air, I'm sure you could set up a stable orbit for that coin. Just like in the universe at large. It seems, AJB, that most effort is put into making GR comply with QM to acheive unification. Meanwhile Loop Quantum Gravity seeks to constrain QM with GR ( like the abolition of an absolute spacetime frame ), yet its not discussed as much as say, Sstring theory, even though it has no need for supersymmetry and additional dimensions. Trying to gain even a basic understanding of the theory is a bear because of the formidable math involved. I don't want to hijack this thred and incur Swansot's wrath, but maybe if you or another member is familiar with the subject, you could start a separate thread/tutorial.
  19. I would have to disagree Swansont. Since the moon is quite large compared to earth, it would experience tidal forces, ie greater on the close face compared to the far face, while all of its fragments would be moving at the same orbital speed. So a lot of the closer fragmenys would sppiral to earth and a lot of the farther fragments would spiral out or even escape (?). But maybe the portion closer to the moon's centre of mass would form some nice rings.
  20. Doc, you DO have a sense of humour. Oh wait, you were being serious.
  21. Well I was going to say that massless particles such as a photon are their own anti-particles, and, if they could possess a charge, couldn't possibly be their own anti-particles anymore. But then i remembered gluons...
  22. Sorry its taken so long to get back Guenter. I realise that the source of Hawking radiation is virtual particles of the vacuum surrounding the event horizon, but they do affect the event horizon. For sufficiently small black holes such that their lifetimes coincide with the lifetime of the universe, ie. they can evaporate, the 'incorporated' virtual particles making up Hawking radiation shrink the surface area of the small black hole until the event horizon disappears and the 'contents spill back out in a gamma ray explosion. So if the information is greatly randomized by entropy into the surface area of the event horizon like a giant book where all the pages are ripped out and tossed in the air ( example by Brian Green ), it is no longer available ( just like entropy 'renders' energy unuseable or unable to do work ) and, so I think, not preserved. It then disappears altogether when the black hole evaporates. So even if you want to say it is 'somehow preserved on the horizon's surface, according to Hawking's own ideas, eventually this surface disappears. I know very little about string theory myself, other than the basics and am not familiar with Susskind's work. But Hawking's resoning for information conservation seems to be based on Quantum mechanical considerations. Maybe its too early to start mixing the apples and oranges of the classical and quantum. Sometimes it works as in Hawking's entropy/temperature/radiation picture, but maybe it doesn't hold up for information since one of his ideas implies the other is wrong.
  23. Sorry guenter, maybe I oversimplified so that everyone can understand, and I wasn't specific enough for you. However I believe both points you addressed were trivial and due to mis-understandings. I believe I did state that the 'frozen star' concept applies to external observers only and that an infalling observer notices no abnormalities in the passing of time. And no I do not believe this to be caused by choice of co-ordinate system. It is an abnormality of space/time itself, and not of the mathematical model used to describe it. And yes your time coordinate is spacelike since the infalling observer's future is a spatial direction ( to the centre of the black hole ) and no deviation is possible. But like I said, I used simple english. But all that was secondary to the point I was trying to make, in response to G. Anthony that intact information could ever be re-radiated via Hawking radiation from a black hole. The black hole part was merely to 'introduce' the main point.
  24. Well I guess its time to add my two cents... When a relatively massive star reaches the end of its sustainable fusion process, it eventually undergoes gravitational collapse. The remaining material which cannot be ejected by a massive stellar explosion, is more or less in free fall towards the geometric centre of the former star, now a black hole. Einstein's equations have the peculiar consequence that the stellar material can continue to exist forever in a state of free fall without ever reaching the bottom. This can be nearly visualised with a Penrose diagram. The space/time in the region of the black hole is so strongly curved that space and time become interchanged. If you are an outside observer, you see the stellar collapse slow down and come to a stop because the direction of time inside the black hole is 'perpendicular' to the direction of time as seen externally, i.e.the only thing in your future once inside the black hole, is a direction ( the geometric centre ).The experiences and observations of the infalling and outside observers are vastly different ( to say the least ). This is due to the purely classical nature of GR. Stephen Hawking came along and introduced a bit of QM and Thermodynamics into this classical picture of black holes, much the same as Max Planck did with his quantization of black body radiation in 1900.. Planck's equation E=hv was a long way from QM which took at least another 25-30 yrs and 50-60 for QED. Similarily Hawking has given us S=kA, where S=entropy, A=area and k is a constant, but like Planck's itt is only a modest beginning. Entropy is very similar to heat capacity and is measured in cal/deg while area is in cm^2. Hawking's constant k, then has a value of about 10^41 cal/deg/cm^2. This is a very large proportionality constant, and since entropy is a measure of randomization, this shows the degree to which any infalling material / energy / information is randomized. So yes, I will agree black holes have a temperature and therefore radiate, and so, if small enough will evaporate and eventually finish with a gamma ray explosion, during our universe's lifetime. But no, I don't agree that information could possibly be conserved after that degree of randomization.
  25. I believe one of the best explanations was given by Richard Feynman in his lecture series ( They are very easy to find online and may even be here as a sticky ). It arises from the fact that the amplitude of the 'wave' is related to probability. Only an infinitely long wave has a clearly defined wavelength, wave number and amplitude. This amplitude is related to a probability in QM, such that in this case the probability of finding a particle at a certain place is the absolute value of the square of the amplitude. And so, in this case, since the wave is infinitely long, it can be found anywhere; position is uncertain. A wave packet on the other hand, has an increasing/decreasing amplitude BUT the wave number cannot be easily defined. so although the particle is more localised in this case, its energy and also momentum are more undefined. It is basically a trade-off, shortening the wave packet locates the particle with more accuracy, but makes the momentum more indeterminate; conversely lengthening the wave packet introduces more uncertainty in the particle position, but makes the determination of momentum more accurate.
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