An reaction follows michaelis menten enzyme kinetics. Km=.001 M, and the initial concentration of substrate=0.840993 M. After 2 seconds, 5% of the substrate has been converted to product.
How much CO2 will be converted after 10, 30, and 60 seconds?
I know the answer is 25% after 10 seconds, 75% after 30 seconds, and 100% after 50 seconds, but I don't know how to get these numbers using the m-m equations: v=d[P]/dt=Vmax*/ +Km
Just looking at the answers, it seems like the reaction rate just stays the same, and 5% is converted for each 2 seconds the reaction goes. However, I feel like this a huge simplification...what was the point of including Km and the initial substrate concentration if this was the case? Is there a way to do the problem that utilizes the m-m equation?
Thanks so much!
