Fuzzwood

Well if i had the choice of placing bugs on a large festering wound or let the limb just rot off...

Not possible as water has a negative solid liquid line

Kill is a bad choice of wording as it is already dead. But in some cases it speeds up recovery as it takes work away from the healing process itself. Still used to treat nasty injuries

Problem is to get it out of your lungs again

That would be the military term for white phosphor

A thorough one? Buy a god damn book

At last sentence: if you dont even know that, get a book before something worse than having to clean the table happens. Also: putting 36V on it is not a good idea. Electrolysis uses Amperage.

Thats what you get when you dont prepare for a practical. Butanol does not yield vinegar when oxidised.

The most sentient thing i can say atm is that 72 is an angle twice as big as 36

1. If it happens before, would you measure any calcium/magnesium? 2. If there isn't a lot of Ca2+, there wont be a lot of CaCO3. 3. You are contradicting yourself there.

According to the link, it smelled like mustard

Nono, its oxidized to benzoic acid first (potassium permanganate is a good option), THEN decarboxylize it.

Just learn how to make basic stuff in notepad. If you ever add something flashy and it is at the wrong location, you can fall back on the stuff you learned with notepad and change its position directly from the code.

Proof? Or is this just a complot theory?

/me just noticed that the rain outside is going sidewards again

Even better, the moment you actually start thinking about those actions, you dont know what you need to do anymore

Dude, please buy a book first, then try to experiment. I guess it was meant for new year for being cool when his hands are blown off.

The additional 4000 µg of lead added to half of the original sample caused a raise of 32 mV. Considering you used only half of the sample, that means you started with 62.5 mV. This means; 4000 µg of lead is the equivalent of 94.5 mV (157 - 125/2). Dividing those gives the response of the detector: 4000/94.5 = 42.4 µg of lead/mV As the sample gave a signal of 125 mV, this means there was 42.4 * 125 = 5291 µg of lead in the swabs.

In both this and prev questions you need the pKa of propanoic acid. For this question, you also need the buffer formulae, which is pH = pKa + log [base]/[Acid].

[math] \forall x \in \mathbb{N} : \textrm{x has a finite decimal expansion} [/math] fixed

Maybe your isp hates you

Im not sure but isnt 18V a bit overkill? I guess you would get better results by shunting the batteries in parallel mode to get a higher Amperage.

Uhm, why do i have the feeling you are going to try a boom-experiment. No you don't get help from me as you cant even spell potassium nitrate right.

/fixed

Besides ethanal being quite toxic, no