Teggle

Thanks for the tips! I'll be sure to use these when writing my assignment!

Thank you all for helping. I asked my teacher and found out what I was doing wrong. Chain Rule: s=0.3cos(pi/4*t) Let u= pi/4*t du/dt= 1*pi/4*t^1-1 du/dt= pi/4 so s= 0.3cos u ds/du= 0.3-sin u ds/dt= ds/du*du/dt ds/dt= 0.3-sin u*pi/4 ds/dt= 0.3-sin (pi/4*t)*pi/4 ds/dt= pi/4*0.3-sin (pi/4*t) And then to find the acceleration: v= pi/4*0.3-sin (pi/4*t) Let u= pi/4*t du/dt= pi/4 so v= pi/4*0.3-sin u dv/du= pi/4*0.3-cos u dv/dt= dv/du*du/dt dv/dt= pi/4*0.3-cos u*pi/4 dv/dt= pi^2/16*0.3-cos (pi/4*t) Thanks

I appologise. I didn't realise I had made a mistake. You are correct, I was supposed to make cos(u) into -sin(u). Making the answer: 0.3-sin pi/4 Thank you for pointing this out. As for how I wrote out my last post, when I was typing it up there was more space between my workings out for ds/du and du/dt. When I posted it, however, it took away the large amount of space I had, making it somewhat confusing to read. I appologise for this as well. My question is, if I change cos(u) to -sin(u), does this then make my findings correct? I am still unsure as to whether I am answering this correctly, and I have to derive 0.3-sin pi/4 to fully answer the question (as I have to find the acceleration), and I am unsure of how to do this with my answer. Maybe you could do an example which is similar to what I have to deal with? Thank you.

Derive the following function to find the velocity and acceleration: s=0.3cos(pi/4*t) Chain Rule: s=0.3cos(pi/4*t) Let u= pi/4*t so s= 0.3cosu du/dt= 1*pi/4*t^1-1 ds/du= 1*0.3cosu^1-1 du/dt= pi/4 ds/du= 0.3cos ds/dt= ds/du*du/dt ds/dt= 0.3cos*pi/4 ds/dt= 0.3cos pi/4 However, with this answer "u" disappears. So I believe this is wrong, but I'm not sure. Any more ideas? To find velocity, you need to derive s=0.3cos(pi/4*t). To find the accelaration, you need to derive the velocity function. So, in the end, s=0.3cos(pi/4*t) is derived twice to get the answer.

Well it would really depend on the ninja's skills wouldn't it? You see, the samurai is heavily armoured, and therefore, protected. However, popular belief says that ninjas are expert fighters, and so maybe don't even need armour. If both subjects had equal skills, then the samurai would have the better chance because of his protection. Yet, one might believe that the ninja, is in fact, quite stupid if he is to turn up to a fight with no means of protection at all... but both subjects would have learned several different styles of martial arts, so then it comes straight back to skill again.

I've been given the question of: Derive the following function to find the velocity and acceleration: s=0.3cos(pi/4*t) I am unsure of how to do this properly with this particuar function. It would also help if someone could let me know how to put this function into Graphmatica. I know you have to go to Tools and then down to Functions to enter it into the program, but I don't know how to write it so it will work, as an error keeps coming up when I try to enter it as I have written above. Thanks to all who can help.