Vastor

well, it's just file sharing website to download power point file. in power point, can't use latex, but i use 'manual arranging' method, thought. (ex. rather than write 1/2, i put 1 with underline, and the put 2 at it bottom) as you can see in the screen shot about side calculation, i think putting the 'bubble chat' is enough about checking the calculations, I think I'll do when I'm done those notes, but, it's not really matter because it can be identified easily, the real problems here is when i got no idea how to get my reader(generally my classmate) to understand my notes, which is very problematic in Quadratic Function. this is because i want to make the notes as self-understood to the reader, would be greatly appreciated if anyone can help. anyway, thnx for reply ^^

hmm, i think i should 'slow down' on my calculation... fortunately, i already learn the Latex, so no more confusing-looking math... and about [math](\frac{2}{2})^2[/math], it's the so-called Completing The Square method, which is actualy mean to be [math](\frac{b}{2})^2[/math] thanks for ur reply btw..

My note i need someone to check the note i made, who know how to 'simplify' and give better idea for better presentation and maybe fix something that wrong in my notes. btw, the most problematic in the notes is Quadractic Function, it's kind of messy and if u got any idea to modify it, post here.. thnx ^^

arbitrarily remove numbers? ermm, u respond to which post actually?

gotcha, ha3, my bad

and there are a law of logs [math] log_a a = 1[/math]

when i checked [math] log_2 2\frac{1}{4} - log_2 (1-3\frac{1}{4}) = log_2 2[/math] [math] log_2 \frac{1}{2} - log_2 \frac{1}{4} = log_2 2[/math] [math] log_2 \frac{1}{4} = log_2 2[/math] and yes, this is fail, i miss something somewhere? from my understanding, the question of 'solve the equation' would mean to be find the value of the unknown 'p', doesn't ?

i having problem of understanding log, the question is solve the equation [math] log_2 2p - log_2 (1-3p) = 1[/math] so, i calculate using this way [math] log_2 2p - log_2 (1-3p) = 1[/math] [math] log_2 2p - log_2 (1-3p) = log_2 2[/math] [math] log_2 \frac{2p}{(1-3p)} = log_2 2[/math] and I'm consider [math]\frac{2p}{(1-3p)} = 2[/math] so [math] p = \frac{1}{4}[/math] confirmed this?

[math]x^2_1[/math]

ha3, nvm, i find after surf on yahoo answer for a while. need confirmation thought. quadratic equation, f(x) = 0 0 = 3x^2 - 6x + 11 -11 = 3(x^2 - 2x) -11 + [3(2/2)^2] = 3[x^2 - 2x + (2/2)^2] - 8 = 3(x-1)^2 f(x)= 3(x-1)^2 + 8 right? then, i check it... 3(x^2 - 2x + 1) + 8 = 3x^2 - 6 + 11 tadaa.. urgh, another problem, ok, it's said. (h, k) is the turning point of the curve y = a(x -2)^2 - 8, another info. y-intercept = -6, determine the value of a, h and k, where (h, k) is the min point so, i got h = 2, k = -8 so, how to determine the a ?

ok, it's said The Quadratic Equation f(x) = 3x^2 - 6x + 11 can be expressed in the form f(x) = 3(x - h)^2 + k. Find the value of h and of k f(x) = 3x^2 - 6x + 11 i use the completing the square method to convert it into vertex form = 3x^2 - 6x + (6/2)^2 + 11 - (6/2)^2 = 3x^2 - 6x + 9 + 2 at this part start to puzzle me, what should i do with 3, which is a = 3 this number appear to be the same at ax^2 + bx + c = a(x - h) + k then, should i remove the 3 from the factorisation? which mean x^2 - 6x +9 +2 = (x - 3)^2 + 2 and then put a to the equation? 3(x - 3)^2 + 2? so, that when i check again, 3(x-3)(x-3) +2 = 3x^2 - 18x + 27 + 2, this is fail. anyone can help?

nice answer, that's what i'm looking for because i made an additional math's note on power point, so, needed an understanding on how those formula formed. thnx.

I'm asking about the Zero Index which is a^0 = 1 can anyone explain 'mathematically' to me how this happen? P.S. how does people write Superscript, Subscript and fraction number in this forum?

ahh i see, so from my understanding, (48/2)y not equal to 48/2y doesn't ??

then, what's the distribution law for '/' ?

ermm, i bit confused here... doesn't that (48/2)y = 48y / 2y so, how can 48/2y = (48/2)y