Dave

er, no, it's some kind of ai stuff recognising certain words in what you type in.

nice.

I read that and thought 'spring?!?' - then I realised you live in NZ so it's 6 months different to over here

I do believe they tried to restrict the selling of games to within certain age groups in Washington not long ago (like 18+ for gta), and I also believe that the games companies basically took them to court and argued it was in violation of the constitution or something. Personally I think it's immoral to sell these kinds of games to kids.

Young's modulus says that stress/strain = Fl/eA (where F is the force, l is the length, A is the area and e is the extension) although it might be strain/stress, can't remember. So if you find the first two, it's relatively easy to calculate the last one.

June, it's my birthday

You have to understand that the ALU operates logical functions at its most basic level. If you want something like that you're talking about a language like prolog (can't remember what type it falls under) which is used to create things like expert systems (for things like medical diagnosis programs, etc).

To be fair, that version that you've got is a very early beta at least, as MS has said Longhorn's not going to be out for quite some time yet.

UNIX is just another OS, although unlike windows it's inherantly a high-end server os.

It's difficult to get your head around the concepts, but it comes with time. However the maths in GR looks pretty nasty, so I won't be taking that module next year methinks ;-) (took special relativity this year)

If you define concept to be 'solving mathematical problems', then yes. If you define it to be 'derived from real-world observations', then I guess not. As I said, it's all down to definition.

Bear in mind that it's only 50% paper, the rest of it is the normal cd materials (for things like protective layer, etc).

MS have been ripping off the mac gui for years. No change there really Can't really see any advantages of Longhorn atm, they seem to be stripping off most of the stuff and putting it into the next release (like the new sql based filesystem). Which means it'll probably never be implemented. Atm, it just looks like another 2000->XP job; keep everything the same and make it look pretty.

Surely it's fairly impossible for an OS to dictate the mobility of the machine?

infinity is not a number - it is a term, and as such doesn't really come into the argument. i has its applications, but it essenially just a definition like all other numbers. When we started doing the counting numbers, we defined one to be a single element, then went on to define 2, 3, 4, etc. These numbers are effectively derived from what we've experienced in the world. The same thing applies to the set of positive rationals - looking at half of a cake, etc. Negative numbers (and indeed any other type of number) are just an extension of this. We've come to learn certain things about the way these numbers work, and so we've derived them ourselves through steps of logic and/or axiomatic methods. I suppose what I'm trying to say here is that numbers don't necessarily have to have an interpretation in the real world; and at the end of the day, it's down to personal belief as to whether you think they are or not (like most things of this nature).

Sleep. A lot. Question: What's your favourite film?

It basically shows that the graph is discontinuous; i.e. there isn't a value of y for every value of x.

Indeed, it just makes for better practice.

[math]s = \int_0^5 v(t)\, dt = \int_0^5 (12t^2-16t) \, dt[/math] So we have [math] s = \left[ 4t^3 - 8t^2 \right]_0^5[/math] And so s = 4*125 - 8*25 = 300 metres. Unless I've made a big mistake (which is quite plausible considering the time). Haven't done springs for about a year now so can't remember anything about them, sorry If you draw a graph, things will become much clearer. First off, a negative value for an integral means that the area lies below the x-axis; so the area is the modulus (absolute value) of the integral. Also realise that when you calculate an integral on a function that moves from being negative to positive (for example, sin(2x) in the region you've given), it's value will not be the area under the curve. I think the integral you'll want to evaluate will be this: [math]\left| \int_{-\tfrac{\pi}{2}}^{0} \sin(2x) \, dx \right| + \int_{0}^{\tfrac{\pi}{6}} \sin(2x) \, dx + \int_{-\tfrac{\pi}{2}}^{\frac{\pi}{6}} \cos(x) \, dx[/math]. As I said, draw a graph. These next two I had no idea how to do I'm not quite sure of the question there to be honest. Perhaps someone else can shed some light on it. Just use the standard formula for rotation of a solid about the x-axis, it's not too hard. You're going to rotate the region bounded by sqrt(x) and the x-axis, then take a conical chunk out of it with y = x-2. Hope this helps

Apparently it's a lot cheaper than the plastic alternative.

For f(x) = 1/x (or indeed c/x, c being in the set of reals) and a = 0, that limit doesn't exist - which is the entire point of being unable to define c/0.

That's the basic decay equation that you'll get for a number of applications (radioactive decay, newton's cooling curve, capacitor discharge, etc). Incidentally, the line where you say [math]\tfrac{1}{x} \, dx = -a \, dt[/math] is not technically correct. What you're actually doing is this: [math]\frac{dx}{dt} = -ax \Rightarrow \int \frac{1}{x} \frac{dx}{dt} \, dt = \int -a \, dt[/math] Then using the chain rule to 'cancel' the dt's from the left hand side integral.

Doubt it'd be that agonising. You'd be turned into kirk pate faster than your nerve endings could react.

If they haven't made it obvious, it's a fair bet that they're not doing one - what's the point of having one and not publicising it?