I think its about time I actually posted an answer to this thread, being that it's been open for absolutely ages
Okay, so you have those two integrals above, namely:
:int: (x/sqrt(x^2+1) + 1/(x*sqrt(x^2+1))dx
First one, as I said, is trivial by using the substitution u^2 = x^2 + 1. That comes out as sqrt(5) - sqrt(2).
The other one is a little harder, but with some thought, it's not too hard. The first thing that struck me was trig substitutions. The x^2+1 sticks out like a sore thumb and it's just crying out for a trig substitution. The correct one in this case is x = tan(t).
Notice that (tan(t))^2 + 1 = (sec(t))^2.
The bounds of integration are x=1 and x=2, so therefore the new bounds with this substitution are t=arctan(2) and t=pi/4.
Now when you use this substitution, it will all cancel down (quite nicely) to:
:int: cosec(t) dt
Which, of course, is a standard integral. If you want to do it by hand, you need to use the subsitution u = tan(t/2). It should cancel down to the integral of cosec(t).
I'll post the numeric answer a bit later, but I'm a bit busy atm.