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Yep, i figured it out already. Thanks.

Hey, can anyone confirm with me that the formula of citric acid is C6H8O7-? or is iit C6H8O7-3? Thanks.

Are you able to neutralize the acid-base reaction? thats what i meant. Sorry. For example. For KOH + HCI KOH + HCI --> KCI + H2O when neutralized by the form of cancellation, it creates: OH + H --> H2O I have to get: C6H5O7-3(aq) + 3H+(aq) + 3NH4+(aq) + 3OH-(aq) --> 3NH4+(aq) + C6H5O7(aq) + H2O(l) to the similar form in the example above. My question is, are you able to neutralize the equation? C6H5O7-3(aq) + 3H+(aq) + 3NH4+(aq) + 3OH-(aq) --> 3NH4+(aq) + C6H5O7(aq) + H2O(l)

I have to cancel out, to get the end product to something like h20. Are you getting any where with that acid-base reaction?

yes that's right.

Hmm.. the neutralization reaction. I guess the equation would have to be something like: 2H + 2O --> 2H20 after you cancel out the compounds.

Oh. Could you please try to get the neutralized form? I can't seem to cancel out right.

Hmmm.. hey, sorry to bother you again. You said the 3 in (NH4) makes the compound neutral? I don't understand that. It doesn't quite work out when I try to neutralize the equation: C6H5O7-3(aq) + 3H+(aq) + NH4+(aq) + OH-(aq) --> 3NH4+(aq) + C6H5O7(aq) + H2O(l) If it's possible, could you try to neutralize it, and give me the neutralized equation so I know if I'm doing it right? Thanks.

Oh I see. Thanks for your help.

hey, I am having trouble neutralizing the reaction now. C6H807 + NH4OH --> (NH4)3C6H5O7+H2O (6C+8H+7O)+(N+4H+O+H) --> (3N +12H) + (6C+5H+70) + h20 Can anyone go any further with cancellation?

Hey budullewraagh, I'm not quite sure about C6H807 + NH4OH --> (NH4)3C6H5O7+H2O could you clarify where the 3 in (NH4)3C6H5O7+H2O belongs to? Is it a subscript for (NH4)? Thanks.

That's great. Thanks a lot!

Hiya, I need some help with this equation: C6H807 + NH3 --> ??? I'm not quite sure what product it creates. Any help? Thanks.