Hi to all great member,
This is my first post on this forum after joining a few days ago. Nice meeting all of science people here....
I am really need clarification on how to calculate the purity of Sodium Meta Bisulfite above. I do the titration with Iodine 0.1 N until the color changes to faint black with starch indicator.
In water the Na2S2O5 + H2O ---> 2NaHSO3.
The purity calculated as:
{(VxNx47.5) / W mg)} x 100% = % w/w Na2S2O5 as Na2S2O5.
Is the above equation correct?. Any other thought?
Google was no help anyway .
Thankyou in advance.
