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Everything posted by thedarkshade
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I'm not good at politics, but I definitely have no idea of what you're talking about!
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What is the number of males or females that post on SFN
thedarkshade replied to Reaper's topic in The Lounge
No, just that the style is girlish. Is it really a she? Damn, I knew it>>! -
Creating nuclear weapons is also scientific, but I don't see the good we get from it!
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Yet you're idealizing the case:rolleyes:...
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OK, fair enough but yet no answer. What is the minimum voltage required to break O2 into atomic oxygen?
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Yes IA! Everyone knows that changes in body temperature have negative effects for the organism. And that's because the enzymes do not work anymore when the temperature changes or fluctuating (even worse). Enzymes are adopted to work in 36-37C and any change will only be harmful to the organism.
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Of course Bignose, I completely agree with you! The problem is that i think they make you fell not so close to the reality, but it's still science and I love it! Cheers, Sh8
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I'm naughty enough! Twice expelled from school's lab for planting explosive chemicals. Once expelled from the school for entering in their database and selling A marks for $5. In the last two years I've changed the school three times. Not allowed to participate in national scientific challenges for high schools for cheating. (not actually cheating but selling a device to the opponent which granted them a complete loss). I'm hell of a naughty guy! Can I get the mad one into the brackets?
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What is the number of males or females that post on SFN
thedarkshade replied to Reaper's topic in The Lounge
Happy to see the percentage ! And I've started to think that iNow is a female:rolleyes:... -
As long as it can be used for the betterment of humanity and other useful cases (scientific research), it absolutely priceless!
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For an internet browser I'd strongly suggest Mozilla Firefox and Safari (the latest versions). They're fast, reliable, secure and elegant. It's worth it to give it a try! Cheers, Sh8
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Trig sheet w/ trig identities and integrals/derivatives
thedarkshade replied to 1veedo's topic in Homework Help
Oh, I didn't know there were sin and cos in LaTeX too! Sorry but I hope you understand this time (although I can see them without problem) Thanks for letting me know Bignose! Cheers, Shade -
Hell no! none of them! Try NOD 32! It awesome!
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Idealized case... That's a thing I have problems with. The calculations and the theoretical procedure goes just fine, but there's just one problem. It does not fit reality, and that is something I do not like. Why do they have to be just for idealized cases? But how can they be for realistic cases, when our world is messily complexed. What an irony!
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Trig sheet w/ trig identities and integrals/derivatives
thedarkshade replied to 1veedo's topic in Homework Help
The very first things you need to know are: [math]sin^2\alpha + co^2\alpha = 1[/math] [math]tg\alpha = \frac{sin\alpha}{cos\alpha}[/math] [math]ctg\alpha = \frac{cos\alpha}{sin\alpha}[/math] [math]sin\alpha = \frac{tg\alpha}{\sqrt{tg^2\alpha + 1}}[/math] [math]cos\alpha = \frac{1}{\sqrt{tg^2\alpha + 1}}[/math] [math]sin\alpha = \frac{1}{\sqrt{ctg^2\alpha + 1}}[/math] [math]cos\alpha = \frac{ctg\alpha}{\sqrt{ctg^2\alpha + 1}}[/math] [math]sin2\alpha = 2sin\alpha cos\alpha[/math] [math]cos2\alpha = con^2\alpha - sin^2\alpha[/math] [math]tg2\alpha = \frac{2tg\alpha}{1 - tg^2\alpha}[/math] [math]ctg2\alpha = \frac{ctg^2\alpha - 1}{2ctg\alpha}[/math] [math]sin(\alpha \pm \beta) = sin\alpha cos\beta \pm cos\alpha sin\beta[/math] [math]cos(\alpha \pm \beta) = cos\alpha cos\beta \mp sin\alpha cos\beta[/math] [math]tg(\alpha \pm \beta) = \frac{tg\alpha \pm tg\beta}{1 \mp tg\alpha tg\beta}[/math] [math]ctg(\alpha \pm \beta) = \frac{1 \mp ctg\alpha ctg\beta}{crt\alpha \pm ctg\beta}[/math] These are the key ones! Cheers, Shade -
Yes, I have seen such thing too, and I think that is due to hydrogens very low density. If you kinda limit it (like putting it in the balloon), it tends to expand and it is that attempt to expand that makes the balloons explode.
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Yes you can get hydrogen from the reaction of acids with metals (although the easiest one i think is with Zn). There are other methods like electrolysis, industrial method, methane heating etc. I don't think inhaling hydrogen or any other gas in lab would me a wise thing. One of the strict rules that every student or professor should follow while working in a chemistry lab is not inhaling directly anything! If you really want to inhale it, then use your hand to pull it gently toward your nose!
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Equalizing equations by oxidation numbers?
thedarkshade replied to thedarkshade's topic in Applied Chemistry
Electronegativity is the ability of the atoms of any element to attract the mutual electronic couple near itself. It is due to changes in electronegativity that water is a polarized molecule. Oxygen has a high electronegativity value (the highest after F) and because of that it takes the mutual electronic cuple nearer to himself and is negatively charged ([math]\sigma -[/math]. And as the couple is moving away from hydrogen, then hydrogen gets positively charged ([math]\sigma +[/math]). And that makes the water possible to create hydrogenic bonds and makes water a key substance! Back to beginning: There are some rules that should be followed in order not to have problems with redox equations and not to have problems with finding out the oxidation numer: 1. Hydrogen is always +1, only in hydrores (NaH, LiH, CaH2 etc..) where his oxidation number is -1. 2. The oxidation number of oxygen is -2, except in peroxides where it is -1 3. The oxidation number of elements in elementary conditions is always 0 4. The oxidation number of a molecule should always me 0 By following these rules you can very easily find out the oxidation number and equalize tricky equations. Cheers, Shade -
Equalizing equations by oxidation numbers?
thedarkshade replied to thedarkshade's topic in Applied Chemistry
I'd go with YT here. [ce]2KBr + Cl2 -> 2KCl + Br2[/ce] This is a redox process because the oxidation numbers of the elements taking part in the reaction have changed. [ce]Cl2[/ce] from the oxidation number 0 has gone to -1, so it has received an electron and has been reduced itself, but it has played an oxidation role. So elements that are reduced, they itself serve as oxidation tools. And the other way around too. [ce]Br2[/ce] from the oxidation state -1 has gone to 0, so it has lost an electron (the one that chlorine got). In this case [ce]Br2[/ce] has been oxidated and itself has served as reduction tool! Just like YT said, oxidation is the addition of electrons. Chlorine has been an oxidation tool in this case since it has given Br an electron and has been reduced itself. Thanks for everything guys! Cheers, Shade -
Equalizing equations by oxidation numbers?
thedarkshade replied to thedarkshade's topic in Applied Chemistry
I took a two-month chemistry course and now I'm fine with oxidation numbers and equalizing equations. Although my relations with my current chemistry teacher are suffering a downfall due to his desire to get all the credits and some horrible things he says (imagine what would be your teacher told you that lightnings have an average voltage of 380V! It drove me completely mad!). Thanks for reply anyway! Cheers! -
If you get to more tricky equations, I'd suggest you to use oxidation numbers. You figure out the changes in oxidation states and then place those number in the molecules in the equation. Watch: [ce]KMnO4 + H2O2 + H2SO4 -> K2SO4 + MnSO4 + O2 + H2O[/ce] it's kinda hard to balance without looking at the oxidation number in this case. The changes that happen here are: [ce]Mn^{+7} ->Mn^{+2}[/ce] so it takes 5 electrons [ce]O^{-1} -> O^{0}[/ce] so it loses 1 but since O is a double-atomic molecule we use 2. Then we just change the places and now where we have Mn we put 2 and where we have O we put 5, se we have: [ce]2KMnO4 + 5H2O2 + 3H2SO4 -> K2SO4 + 2MnSO4 + 5O2 + 8H2O[/ce] It's a bit tricky but very useful!] Cheers, Shade
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I'd go with post #2! You could refer to gravity using the classical newtonian formula: [math]F=G\frac{m_1m_2}{r^2}[/math] You can refer to gravity as a force that acts between any to objects and is directly depended from their mass and indirectly from the distance. That means the heavier the mass, the higher gravitational attraction, the larger the distance the smaller the gravitational attraction. But what gravity actually is I personally think is kinda mysterious. Another explanation would be that gravity turns out to disortions in space-time fabric...
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I think what you have seen seems to be a picture which is often used to show the expansion of the universe, or better say the evolution of universe. I have seen such pics too and they usually progress at one side (which I don't understand)! And the "big yellow thing", I suppose (i'm not sure since I haven't seen what you have) refers to the Big Bang. But one thing you must get straight is that Big Bang was not an explosion, because it is often called the ancient explosion that created everything. So what is Big Bang? Well, it is the creation of everything from nothing all at once!