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Everything posted by thedarkshade
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Well in school they teach you according to the books implemented by the government, so if they've said "Energy is the ability to perform an action", that is because that was written in the books that we were supposed to finish that year! edit: and I just read one of Richard Muller's writings and the first line into Definitions chapter is: Energy is the ability to do work!
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to what?
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Stubborness or curiosity? Cool
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I just heard this joke from my friend and I really found it funny.
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as you surely know the formula is: [math]n=\frac{m}{M}[/math], and as you have only the density, then you find it through [math]m=\rho \times V[/math], when V=1[math]1dm^3[/math]. So (I think) it goes like this: [math]m=\rho \times V= 2.23\frac{g}{cm^3} \times 1000cm^3=[/math] [math]m=2230g[/math] Then you find the moles by: [math]m=\frac{m}{M}=\frac{2230g}{12 \frac{g}{mol}}=185.8 g[/math] What you did here is you put density instead of mass. According to your datas, it's density that is 2.23 not the mass!
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Yeah, you're right! It just has to maintain the balance somehow! Thanks for the info;) !
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You have A class (even PhD) biology here in SFN too. Anyways, try this, and if there's any problem just let me know!
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What do you not like about SFN?
thedarkshade replied to Cap'n Refsmmat's topic in Suggestions, Comments and Support
That'd be just great! -
What do you not like about SFN?
thedarkshade replied to Cap'n Refsmmat's topic in Suggestions, Comments and Support
take a look at thread "don't tell me..." I had to cut down nr 1. 2. and 3. so they fit... but then I was lost... it took me time to put them in the right place... not any detailed procedure, just long ones! -
What do you not like about SFN?
thedarkshade replied to Cap'n Refsmmat's topic in Suggestions, Comments and Support
What I don't like?? Hmmm there's not enough room for long mathematical procedures! I need to cut them to make them smaller so they fit, and then I lose the sense about "what was I doing"!!! -
So its: [math] x = 3 \sqrt{(x+3)^3 - (x+1)^3 + (x+8)^3)} [/math] I separated the equation to make it e little easier, so for those three parts I got : 1. [math](x+3)^3=(x+3)^{2}(x+3)=(x^{2}+6x+9)(x+3)[/math] [math]=x^{3}+3x^{2}+6x^{2}+18x+27= x^{3} + 9x^{2} + 18x + 27 [/math] 2. [math](x+1)^3=(x+1)^{2}(x+1)=(x^{2}+2x + 1)(x+1)[/math] [math]=x^{3}+x^{2}+2x^{2}+2x+x+1=x^{3} + 3x^{2} + 3x + 1[/math] 3. [math](x+8)^{3}=(x+8)^{2}(x+8)=(x^{2}+16x+64)(x+8)=[/math] [math]x^{3}+8x^{2}+16x^{2}+128x+64x+512=x^{3} 24x^{2} + 192x + 512[/math] And after we do the operations inside the root we get: [math]x^{3} + 30x^{2} + 207x + 538[/math] So if I'm correct the equation now is: [math]x^{3}=x^{3} + 30x^{2} + 207x +538[/math] As we have the same [math]x^{3}[/math] on both sides, then we eleminate it, and then it looks like this: [math]30x^{2} + 207x +538[/math] And the rest is easy! I hope I haven't made any stupid (forgotten something) mistake!
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You want me to bring you a clip where you can see him saying that? Jesus:doh: !!!! I'm 100% sure he said that! I just asked him again 30mins ago! And I'm not saying that this is the scientific name, but I'm just saying what he told me to when it comes to that!
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I think he is right! When we talked about energy on my physics classes the definition they gave to us was: "The ability to perform an action!"!, and that's it! I went into further details to learn more but at school they only said that and moved into formulas!
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Yes indeed! Thanks;) Great info for novice!
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Is there evidence (or not) that c has changed over time?
thedarkshade replied to CLJ's topic in Relativity
Ok, thanks for the link. I requires a username and a password. I guess I'm gonna be a new memer;) ! -
I'm telling you, he told me they're called that way! The guy has a PhD on genetics, and he's currently on of the top 10 european scientists working in cancer, so I guess he knows more things then must of us here about genetics. I'm just using the words that he told me!
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Huge Huge Huge, but awesome. Here's another "drop" compared to what farsight wrote!
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Once I had a project that had to do with nucleic acids, and came across an info that states that there are some cases when RNA contains thymine! Right next to my door lives a person who's got a PhD on genetics, and I asked him about this, he told me that there are some specific cases when thymine is located in RNA, and he said that in these cases RNA can me called "single-chain DNA" or "double chain RNA".
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300 mpg car coming to the next parking space soon
thedarkshade replied to Realitycheck's topic in Other Sciences
I was just about to write that! -
When we learned about pH, we mentioned that water can function as base and also as acid ([ce]H2O ->[/ce][math]H^{+} + OH^{-}[/math]) and we also mentioned that the the product of these two represents the ionic product for water : [math]Kw=[H^{+}][OH{-}]=10^{-7}\frac{mol}{dm^3}\times 10^{-7}\frac{mol}{dm^3}=1\times 10^{-14}\frac{mol^2}{dm^6}[/math] But this product is when the temperature is round 25C (or a bit lower), because this product changes with temperature. For example, in 50C the ionic product for water is 5 times greater than in 25C, and in 100C the product is 50 times greater. So could this be the reason why Mg + H2O forms different substances in different temperature? [ce]Mg + H2O -> MgO + H2[/ce] (cold water) [ce]Mg + 2H2O -> Mg(OH)2 + H2 [/ce] (hot water) So is the answer "the ionic product for water"?
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Death Metal is the one! I just love it!!! I love The red chord
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The Official "Introduce Yourself" Thread
thedarkshade replied to Radical Edward's topic in The Lounge
Hi everyone! My name is Rinor Berisha, but my friends call me Draz (don't know why!), but I like being called Shade!!! Strange huh!!! -
If you're thinking of decomposing H2O2 into H20 + O2 , then you don't really need to do anything, because H2O2 is not stable itself! All it need is sun rays and it will break into H2O + O2, I think!!!
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Help needed in extraction of polymers
thedarkshade replied to sathish_1707's topic in Science Education
I didn't man, but I just think that stuffs here just got to be a "little" more formal, that's all!