Jump to content

LMHmedchem

New Members
  • Posts

    1
  • Joined

  • Last visited

Profile Information

  • Favorite Area of Science
    Chemistry

Recent Profile Visitors

The recent visitors block is disabled and is not being shown to other users.

LMHmedchem's Achievements

Lepton

Lepton (1/13)

0

Reputation

  1. Hello, I have some data, (x,y) (2, 0.356) (3, 0.543) (4, 0.724) (5, 0.905) (6, 1.086) (7, 1.267) (8, 1.448) (9, 1.629) (10, 1.810) (11, 1.991) (12, 2.188) (13, 2.364) the x,y plot is linear and the correlation R is 1. The y value is a coefficient and I would like to non-linearize the coefficioent to create the following conditions; when x=2, y=1 when x=13, y=2 when x=7, y=4 If I apply a parabolic transformation y= A*(x^2) + (B*x) + C with, A = -2.42 B = 7.1 C = -1.222 I get close, but the maximum values is at x = 8, y= 3.985 This is the transformed x,y data (x,y) ((2, 1.0) (3, 1.920) (4, 2.650) (5, 3.222) (6, 3.635) (7, 3.889) (8, 3.985) (9, 3.922) (10, 3.700) (11, 3.320) (12, 2.729) (13, 2.040) I need to shift the relative maximum of the parabola to be at x=7. What I have so far was done by trial and error, but there must be atheorem that would allow me to solve for the correct polynomial andback engineer a solution. I have attached an excel spreadsheet with the data and plots in case that helps. Please feel free to move this post if I have put it in the wrong forum and thanks in advance for any help you can give. LMHmedchem distance-ratios_post_11-07-12.zip
×
×
  • Create New...

Important Information

We have placed cookies on your device to help make this website better. You can adjust your cookie settings, otherwise we'll assume you're okay to continue.