The tyres will have an elasticity, which I'm going to foolishly assume is linear for this purpose. Assuming the overall spring constant of the four tyres to be k, when the car is sitting on the ground in equillibrium,
kx=mg,
where x is the deflection of of the tyres, m is the mass of the car, and g is the acceleration due to gravity.
For the car to be just lifted off the ground, it should be raised by x. In doing so, the increase in gravitational potential energy will be mgx, whereas the decrease in elestic energy will be (kx^2)/2. Thus the total energy change (the energy provided to the car) is
mgx-(kx^2)/2.
Using x=mg/k from the equillibrium equation above,
Energy required= ((mg)^2)/k-((mg)^2)/2k
=((mg)^2)/2k
Edit: I forgot that the mass was given...
Of course, tyres never behave linearly, so being lazy enough to assume that a pound is half a kilogram and g is 10 m/s/s would be the least of our worries and doing so gives (50/k)MJ.