So for the first reaction, I'm assuming that methylcyclohexane with Br2 (and light) will form 1-bromo-1-methylcyclohexane (because there's a tertiary hydrogen). Taking that through the 2nd rxn with yeild 1-ethoxide-1-bromocyclohexane (ethoxide=strong base in protic solvent)
Hopefully I am right, i have no way to check the answer. I tried to search but could not find an answer and want to know if my logic is flawed or not. Also, is there going to be an E1 (minor) rxn after adding sodium ethoxide? or not?
I appreciate anyones help.
