Maqboole

You are offered to finance a compressor , with a nominal interest at 8.2% compounded monthly. YOU PAY £590 PER MONTH FOR 134 MONTHS. Estimate the total amount of money to be paid . I would like some help in this ,i was m trying to do economics exams preparation .i would like can someone suggest me a solution or which site should be helpful. i would be very thankful, plz tell me if i m wrong what i did is i multiplied 11.2 yrs by 8.2 then multiplied £590. is that the correct way. Maqbool

thx for your kind reply i have seen the link you sent me. i have seen the three formulas givens for the reynolds numbers but i dont understand whihc one to put as you see the 1st one is (density x mean fluid velocity x length of the object / dynamic viscosity ) if we see we have all the information we need to find reynolds numbers but we are also asked to find the dynamic viscosity . so that does not fit here all are to me used if the dynamic viscosity of is given . So i m still confused . waiting for your kind reply Merged post follows: Consecutive posts mergedOk this is what I have tried. I tried using the two formulas which come close to solving the problem. [math] u® = Vc [1-(\frac{2r}{D})^2] [/math] and [math] V = \frac{\pi*R^2*Vc}{2*\pi*R^2} =\frac{Vc}{2}=\frac{\Delta p*D^2}{32*\mu*l}[/math] if i use the 2nd formula, then I can calculate [math] \mu [/math] by making it the subject and doing the arithematics but the question, as I am sure you would have noticed by now, doesnt give the length or the pressure difference so I have more than 2 parameters missing rather than 1. Does anyone think that we can assume the pressuse as 1 atm (as it is constant) and the length as 1 m to get [math] \mu [/math]? If I do that I get [math] \mu = 7440 [/math] any help now please.

Hi I am trying to solve this i really help .anyone i would be thankful. Fluid of specfic gravilty 0.06 flow in a long vertical 2.56 ^10-2 m diameter pipe with average velocity of 0.15m/s .if the preasure is constant through the fluids,what is viscosity of fluid? assume laminar flow/ i) Determine the shear stress ii) Viscosity of the fluid iiI) Dertermine Reynolds numbers i tried that i used my best to put reymonds number which is shown in following link. http://en.wikipedia.org/wiki/Shear_stress but i couldt . i hope you would be able to help me thx.

hi i m trying do this question but i just dont understand how .i would be thankful if someone guides me . 1 :- The wall shear strees ina fully developed flow portion 0.3m diameter pipe carying water is 89 pa. dertermine the preasure gradient(Pa/m) if the pipe is a :- Horizontal b :- Vertical with flow up or c :- Vertical With flow down. 2:- A viscous fluids flows in a 0.10m diameter pipe, such that its velocity is measured 0.012m away from the pipe wall si 0.8 m/s. if the flow is lamiaar. Dertermine the center veocity Dertermine the flowrate/. Thanks .

I didt get this answer at all i got something else this is the answer what we are told by our teacher. I wanted to use the formla A=Q/Utln For that i used the formula Q=m cp t then i used the formula for calculating tln = (t1-t2)/ln(t1/t2) we are given u now when we use that we dont get the right answer

Plz help i just dont knwo how to solve it i just want a little help.thz Water at the rate of 68kg/min is heated from 35 to 37 C by oil having a specific heat of 1.9kj/kg C. The fluids are used in a counter double pipe heat exchanger, & ayhe oil enters the exchanger at 110 C & leave at 75 C/.The overall heat transfer coefficient is 320 W/m^2 C. Calculate the heat exchanger area. Answer is 15.82 m^2

I have an other problem of the same nature now. I have understood the question well but i dont understand what formula should be used for the solution. Answer to the question is 7.579 W/m2 C 19 W Water at 50 C flows inside 25cm diameter tube such that hi 350Wm-2 k-1.The tube has a wall thickness 0.8 mm with thermal Conductivity of 16W m-1 K-1.The outside of the tube loss heat by free convection with hoof 7.6 Wm-2 k-1. Calculate heat transfer cofficient & heat loss per unit lenght to surrounding air 20C.

Thz a lot i did get the solution & i did it right.Thz a lot if you would like i can explain that to you.

first of all i would like to say my thank to CaptainPanic. In helping me in that question i would like to inform you that i did manage to calculate Gr & Pr .so i multiplied them & my answer came up as 3.08x10^9. What to do next now i am confused . yes i have the answer of the question answer is 1953 W. Can you help me Thx

Hello i was working on my crousework on Thermodynamics of chemical engineering i would like to ask for help as i would be vevry appriciateable & other might benifi from it too the question is . Calculate the rate of hear transfer from vertical plate of side length 1m ,if its surface temperature is 500k & air flow by the plate due to natural convection,at a temperature of 300k. Data: For air viscosity ; 1.9x10^-5 kg m-1 s-1 specific heat capacity ;1.01 KJ kg-1 k-1 Cofficient of cubical expansion : 3.33x10^-3 k-1 Density ;1.165 kg m-3 thermal conductivity;0.0337 Wm-2 k-1 Gravity; 9.81s-2 For Lamimar flow: Nu = 0.59 [Gr.Pr]^0.25 For Turbulent Flow Nu=0.13 [Gr.Pr.]^0.33

Intergrate by parts: ∫ x(x +1)^4 dx X . ∫( x+1)^4 - ∫(∫(x+1)^4) . dy/dx (x) X. (X+1)^5 /5 - ∫(x+1)^5 /5 . 1 X. (X+1)^5 /5 – (x+1)^6 /30 +C. This is the best I can go. Our A’level teacher says its fine to do it till here, but the book has simplified answer I want to get to. Could someone tell me how to reach to the answer of (5X-1)(X+1)^5 /30 + C. Help appreciated !

This is the same problem I have actually. I think I need to relook the question and tell whether I have stated wrongly or not. My apologies if I have though!

Hi there I hope you people must be doing well & if you be kind enough to please help me in my problem I would be grateful thx. Maqbool This is Physics question related to ideal gas Q: A uniform capillary tube, closed at one end, contained air trapped by tread of mercury 85mm long. when tube was held horizontally , the length of the air column was 50mm. when it was held vertically with a corked end downward The length was 45mm. find the atmospheric pressure. take g=10 Density of mercury; 14 x 10^3 How to solve it I tried it answer comes 5, use p=density x gravity x change in length Ans should be 1.01 x 10^ 5 (according to Mark scheme). PS. I need urgent help please, Ok don't give the answer but at least direct me to the solution! Thanks!

interesting

Hi, I was wondering how you calculate bond lengths of HCl? Infra-red spec is an option which uses the mechanism of vibration to determine the functional groups. I want to know would this technique aslo be used to find the bond length of HCl? If so then should not HCl be in Gaseous state? Thank You

hi can some one help me in balancing equcations? i would be thankful

Hi i need help here plz can someone explain Kinetic Theory of gases & molecules .With root mean square speed & how to calculate it. Thanks Maqbool