little boy

HCI (s) <=> H+(s) + Cl-(s)

Is there many kinds of infinity? e.g. some infinity is larger that other infinity such as lim x->0, 1/x=infinity and lim x->0, 2/x=infinity both are equal to infinity, but actually the "second infinity"=2*"first infinity"

Are there any alternative computing engine of WolframAlpha?

the video is wrong and misleading! They play trick! The two series start at the same time. That means the upper"2" doesn't start with the lower"-2", instead it start with lower "-1", and then after you cancel out the upper number and lower number, that will be 1+2+4+8....... (the same as the original one), then you get the right answer as infinity!! I think the above is the simplest way to explain. Is it helpful?

"undefined" has no meaning, how does it result in 1/undefined = 0?

The page states : "Nevertheless, there are hydroxide ions there, and we can squeeze this into the Arrhenius theory." so I think it is Arrhenius base

Is NH3 a Arrhenius base? I don't know whether a Arrhenius base requires a OH- in the molecule.

wow.. very detail

yes, They are chemical reactions.

Is it legal to simplify a->b->c as a->c a <=> b <=> c as a <=> c ?

Why is NH4Cl(aq) acidic and CH3COOHNa(aq) basic?

I said it is not a limit, and it is 1/(1/0), not 1/0.

1/(1/0)=? (not limit) Is it zero or undetermined?

w=R1, x=R2, y=R3, R4=z, s=R5, v=voltage of cell, a=voltage of point A, b=voltage of point B, then, Inputting"a-(a-s*((v-a)/w-a/x))=s*((a-s*((v-a)/w-a/x))/z-(v-(a-s*((v-a)/w-a/x)))/y), solve a" on wolframalpha, then a is found Inputting"(s*(b/z-(v-b)/y)+b)-b=s*((v-(s*(b/z-(v-b)/y)+b))/w-(s*(b/z-(v-b)/y)+b)/x), solve b"on wolframalpha, then b is found It is certainly correct as I have tested it many times. I had been calculating it for about 6 hours.(so crazy..... )

How is V1-V2 (stage 3, point 6) used in calculation? Why is it needed to know? clear image