little boy
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Is there many kinds of infinity? e.g. some infinity is larger that other infinity such as lim x->0, 1/x=infinity and lim x->0, 2/x=infinity both are equal to infinity, but actually the "second infinity"=2*"first infinity"
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Are there any alternative computing engine of WolframAlpha?
little boy posted a topic in Mathematics
Are there any alternative computing engine of WolframAlpha? -
the video is wrong and misleading! They play trick! The two series start at the same time. That means the upper"2" doesn't start with the lower"-2", instead it start with lower "-1", and then after you cancel out the upper number and lower number, that will be 1+2+4+8....... (the same as the original one), then you get the right answer as infinity!! I think the above is the simplest way to explain. Is it helpful?
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"undefined" has no meaning, how does it result in 1/undefined = 0?
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The page states : "Nevertheless, there are hydroxide ions there, and we can squeeze this into the Arrhenius theory." so I think it is Arrhenius base
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Is NH3 a Arrhenius base? I don't know whether a Arrhenius base requires a OH- in the molecule.
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yes, They are chemical reactions.
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Is it legal to simplify a->b->c as a->c a <=> b <=> c as a <=> c ?
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Why is NH4Cl(aq) acidic and CH3COOHNa(aq) basic?
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I said it is not a limit, and it is 1/(1/0), not 1/0.
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1/(1/0)=? (not limit) Is it zero or undetermined?
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w=R1, x=R2, y=R3, R4=z, s=R5, v=voltage of cell, a=voltage of point A, b=voltage of point B, then, Inputting"a-(a-s*((v-a)/w-a/x))=s*((a-s*((v-a)/w-a/x))/z-(v-(a-s*((v-a)/w-a/x)))/y), solve a" on wolframalpha, then a is found Inputting"(s*(b/z-(v-b)/y)+b)-b=s*((v-(s*(b/z-(v-b)/y)+b))/w-(s*(b/z-(v-b)/y)+b)/x), solve b"on wolframalpha, then b is found It is certainly correct as I have tested it many times. I had been calculating it for about 6 hours.(so crazy..... )
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How is V1-V2 (stage 3, point 6) used in calculation? Why is it needed to know? clear image
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what happen after the switch is closed? I am confused.
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Thank, now I am clear How does it deduce that V1=R1/(R1+R2) x V while R1 and R2 are not in series? (highlighted) image link
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Then it is incorrect to say that R1 and R2 are in series?
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My link Is it correct to say that R1 and R2 are in series , R1 and R3 are in parallel? God bless the people answering me. Is there a simpler equivalent circuit?
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now I understand, thankyou
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My link This is a the page of my exercise. After the switch is moved to position B, it says a parallel circuit is established, but circuit seems not completed because one terminal of the cell is not connected.
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God bless the people answering me.
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What is electric breakdown? Can anyone explain it briefly? The results from Google are too complicated and not understandable.