Hi:
For the reaction:
Fructose 1,6-bisphosphate (F-1,6-BP) ↔ DHAP + GAP
The standard free energy change, ΔG°', is -23.8 kJ/mol
Suppose that in a mammalian liver cell at 37 °C (310 K), the actual metabolite concentrations are as follows:
[F-1,6-BP] = 1.4 x 10–5 M
[DHAP] = 1.6 x 10–5 M
[GAP] = 3 x 10–6 M
Calculate the actual free energy change (ΔG) at 37 °C (310K).
Question options:-56.2 kJ/mol
-23.8 kJ/mol
-8.6 kJ/mol
-3.2 X 104 kJ/mol
I chose -56.2 and repeated all the calculations several times, but it doesnt seem to be the right answer, please let me know any mistakes thanks.
-23.8+0.00831(310)ln((1.6x10^-5x3x10^-6)/(1.4x10^-5))=-56.2
