I think Jacques has the right answer: mass "eats" space around it.
The dimension mass interact with dimension space-time in a way that it "leaks-out" or "delete" space-time in a steady rate.
Think of spreadsheet as space-time, a photon travels from cell to cell at constant speed c. A mass is an interaction (string or cord) from space-time dimension to the mass dimension, in a way that it delete one cell every given time.
In a spreadsheet, when you delete a cell, all other cells are shifted instantaneously. The same effect happens in space-time dimension: a space deleted by a mass affect the whole univers instantaneously: that's the force of gravity.
When a critical mass is located at the same area, it "deletes" space at such a rate, that even mass-less photon can not escape from it. It's like the cells are deleted at the same rate as the speed of light moves from cell to cell.
When an object/satelite rotates around a big mass, supposedly it's momentum takes him on a straight line, but since the space between him and the big mass disapear at a constant rate, the satelite takes a circular trajectory. That's the gravitational force at work. In fact the satelite travels on a straight line, but it's the space that warps around.
Two motionless objects in an empty space will find the space between them disapearing at a constant rate, and they'll end up closer to each other (at the rate proportional to the product of their masses).
When we move at a certain speed near a big mass, one cell at a time like in a spreadsheet, the spaces deleted by the mass make us think that the time is slower, like if we play monopoly or other board game, and the place behind us is deleted. We rolled 6, and moved 6 places but it ends up only 5 places from where we were. The time to make a round seems longer. That's the relativity of time that turns slower near a big mass.
If G is around 6.6 10E-16 cm3 g-1 s-2, then each gram of mass deletes approximately 2.56 E-8 cm3 per seconds.
It's papenoir's theory, any comment is welcome.
