The overall length of a piccolo is 32.0 cm. The resonating air column vibrates as in a pipe that is open at both ends. a. Find the frequency of the lowest note a piccolo can play, assuming the speed of sound in air is 340 m/s.
b. Opening holes in the side effectively shortens the length of the resonant column. If the highest note a piccolo can sound is 4000 Hz, find the distance between adjacent antinodes for this mode of vibration.
Open-Open system, so Lambda=2L (1st Harmonic, Am I right here?) =2(0.32m)=0.64m
Frequency=340m/s / 0.64m=531.25Hz ----------->a. Is that right?
b) F=4000Hz, Distance=x, antinode = 1/2 of Lambda? so 0.16m ------------> Is that right?
I am confused at this point.