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Odd....when I set it to full screen it played in Media Player. edit: I'm retarded. It's in Quicktime and Media Player

Unanswered posts, eh? Like this one?....until NOW!

So that's how you got Blike's pants...

This quote says it all.

If you have Windows Media Player, you can watch it anytime. The link is up a few posts.

Sometimes it works, sometimes it doesn't.

Don't forget the capitalization of "Creator". They even capitalize pronouns when talking about Him.

As do most of the threads I post in.

It took you that long to figure it out? ATOMIKPSYCHO IS A GOD!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Yes, the dots expand. They aren't made of one ink molecule! The distance between the individual drops of ink expand as well(not just the rubber between the dots). You just said that you tried it, and your results indicate that I was right.

No. You do!

I can simulate space travel by walking across a room.

So, if you draw two dots on the balloon before blowing it up, they are the same distance apart inflated as they are deflated? Perhaps you should actually try it. Things you will need: 1) A balloon 2) a tape measure(or a roll of string and a ruler) 3) a marker Take the marker and make two marks on the balloon. Measure the distance between the marks and record it. Inflate the balloon. Measure the distance between the marks again, and record it. Are the two distances equal? If not, which distance is greater?

Which bits of the surface of a balloon get closer when it is blown up?

Am I the only one thinking that since the car is 2000lbf, it will take any force greater than 2000lbf to lift it(assuming you lift from the centre of gravity with no pulleys and such)? edit: I somehow missed the post directly before mine.

What does Lagrangian mean in terms of modern and theoretical physics?

No such thing as a perfect vacuum. Lubrication doesn't take away friction; it changes the kind of friction.

Air resistance? Friction?

Write in for Ton Swanson

uhhh, no breaks in the graph

[math]\vec{F}=\frac{d}{dt}\vec{\rho}[/math] renders as [math]\vec{F}=\frac{d}{dt}\vec{\rho}[/math](and shouldn't that be a partial derivative?)

And you can view it online starting friday.

I think this is the most correct thing he's said yet.

Priceless.

For sake of discussion, I'll repost the Dawkins quote.