ydoaPs

so europeans brought tools to africa? i remember history saying the opposite

Shawn said he will. (follow it, not post)

here are some differentiation rule thingys: if u, v, and w are differentiable functions, and c and m are constants, then: [math]\frac{d}{dy}©=0[/math] [math]\frac{d}{dy}(x)=1[/math] [math]\frac{d}{dy}(u+v+...)=\frac{d}{dy}(u)+\frac{d}{dy}(v)+...[/math] [math]\frac{d}{dy}(cu)=c\frac{d}{dy}(u)[/math] [math]\frac{d}{dy}(uv)=u\frac{d}{dy}(v)+v\frac{d}{dy}(u)[/math] [math]\frac{d}{dy}(uvw)=uv\frac{d}{dy}(w)+uw\frac{d}{dy}(v)+vw\frac{d}{dy}(u)[/math] [math]\frac{d}{dy}(\frac{u}{c})=\frac{1}{c}\frac{d}{dy}(u),c\not=0[/math] [math]\frac{d}{dy}(\frac{c}{u})=c\frac{d}{dy}(\frac{1}{u})=-\frac{c}{u^2}\frac{d}{dy}(u),u\not=0[/math] [math]\frac{d}{dy}(\frac{u}{v})=\frac{v\frac{d}{dy}(u)-u\frac{d}{dy}(v)}{v^2},v\not=0[/math] [math]\frac{d}{dy}(x^m)=mx^{m-1}[/math] [math]\frac{d}{dy}(u^m)=mu^{m-1}\frac{d}{dy}(u)[/math] ha dave, i beat you to it.

no

i don't remember. there was another one too, i think.

i already made two threads on this. search "circle"

my blog rules the eart, though i am rather boring. http://www.xanga.com/yourdadonapogostick

do you have a blog?

so, the wave-packet can move faster than the photon?

does light also have a probablility wave?

how can the wave be faster than the particle?

i think an IM type thing would be better. it is hard to post and chat at the same time.

good point. i guess ur right.

how bout [math]a^\frac{b}{c}=(\sqrt[c]{a})^b[/math]? doesn't that work?

well europe is both.

no, Kal-el

i only started this last summer and i can already see a lot of change. when i read some of my early posts, i can barely believe that they were mine.

i can see the f(g(bla bla bla)) way, but how do you do it the other way. maybe i should just wait until you get to it. edit: it would appear that with logarithms, you do what i said a few posts ago.

[math]D_x(f(g(x)))=f'(g(x))g'(x)[/math] or,if y=f(u) and u=g(x), [math]\frac{dy}{dx}=\frac{dy}{du}\frac{du}{dx}[/math]?

i got a book "Schwams outline for calculus", or something like that, from the library, because i like to see where things are going. all of the diferentiation rules make sense except the trig and log differentiation rules. for log, it says [math]\frac{d}{dy}(log_{a}x)=\frac{1}{x}log_{a}e,a>0,a\not=1[/math], but it doesn't say how to do it with a function. the examples seem to suggest that you would replace x with the function and then [math]\frac{d}{dy}(log_{a}x)=\frac{1}{x}log_{a}e\frac{d}{dy}(x),a>0,a\not=1[/math]

i wrote bob an e-mail and here is the response "Hi Nick, Actually Bob hates the topic of UFOs and his past experiences at the Nevada Test Site. He never discusses the topic anymore - not even with his wife. If you are interested in talking to Bob, I'd pick another topic.... -Frank"

isn't potential a scalar?

i don't believe you. i thought you looked familiar.

http://www.starfleetarchive.com/

so, with both ends closed, it is [math]((2{\pi})^{\frac{1}{3}},2(2{\pi})^{\frac{1}{3}})[/math]