DerekTX

Your physics is right. Using what you did I got 1.35*10^-3 This is exactly right. I just don't understand why. to me, in my mind, the formula ought to be [math]R=rho*L/dA[/math] but then I wind up with what darkenlighten has, which is wrong. I don't understand why the L magically goes away and you integrate the entire [math]1/4pir^2[/math] expression. happy dead thread-aversary.