Hi guys
I have a grade 12 highschool lab tomorrow and i dont understand one of the questions
The question is as follows:
The balanced chemical equation for the reaction is as follows:
2KMnO4+ 5H2C2O4+ 3H2SO4 ----> K2SO4+ 2MnSO4 + 8H2O+ 10CO2
Account for the different rate when the second portion of potassium permanganate solution was added to test tube #1. (Look at the products carefully for a clue).
(Test tube 1 is a repeated version of another test tube experiment which consisted of 5 ml of oxalic acid, 10 ml of sulphuric acid 10 ml of tap water, room temperature and 2 ml of KMnO4. The difference between both is that the repeated version took 74s to react and the first version took 180s to react.)
Thanks!
