For the "Borohydride Reduction of Vanillin to Vanillyl Alcohol" reaction, the equation is:(NOT looking for the procedure, but the hypothetical amount of each compound needed)
4(vanillin) + NaBH4 +4H20 --(in NaOH solution)-->> 4(Vanillyl alcohol) + H3BO3 + 4NaOH
If the starting material is 25 mmol of vanillin, how much
Sodium Borohydride___,
Sodium Hydroxide___
HCl___
is needed to complete this reaction?
25mmolx(1 mol/1000mmol)x(152.2 M.W./1 mol)=.4g (400mg) of vanillin (the starting material). But from here, can someone show how much the rest of the chemicals are needed?
The Physical Properties
Vanillin - 152.2 M.W.
Sodium Borohydride - 37.83 M.W.
Vanillyl Alcohol -154.2 M.W.
(PLEASE show the calculations )
Oh, and for HCl it's (3 M), and for NaOH (1 M)
