psi * psi

I'm not sure if this is in the right forum, but it's not a homework problem, so I thought I'd ask it here. This may be an obvious answer that I'm overlooking, but I'm curious. In the case of a complex such as [Ru(phen)2(qdppz)]2+, I KNOW that qdppz (quinone phased dipyridophenazine) is the intercalating ligand, but I don't know why. Why does qdppz intercalate and not the phen ligand? Thanks!

bump?

If they were, that wouldn't explain why t2g is lower in energy. my notes say that t2g is lower in energy because of the geometrical arrangement of the orbitals- in the t2g arrangements, the orbital lobes are directed in between the bonds of the ligands instead of along them.

in octahedral, t2g orbitals can't overlap so are nonbonding. does that have to do with its energy difference?

I have a question that asks me to divide the d orbitals of the metal atom in the trigonal prismatic ML6 complex into their symmetry types. I've answered this part of the question, but I'm not sure I answered the question the problem was asking. Does it just mean look at the character table (D3h) and say: dz2=A1' dx2-y2, dxy= E' etc? Then the question asks to predict the relative energies using CFT. I have dz2>dx2-y2>dxz, dyz>dxy, but I'm not sure that's right...

The example you just gave is one of the isomers I have. Which means I'm not completely off . Can the example you just gave have an enantiomer? Because I see one... I also have: bpy: eq amine: axial amine: axial H2O: eq Cl: eq ^^ which also seems like it'd have an enantiomer...? Then I also have: bpy: eq amine: axial H2O: axial Cl: eq amine: eq which I don't THINK is repetitive since I haven't had amine and water trans to each other yet. same with the next one since I haven't had chlorine and amine trans to each other either. Am I completely off base? bpy: eq amine: ax H2O: eq Cl: ax amine: eq

for bpy being eq-eq, I get one configuration with the amines being trans (ax-ax) and the others being cis, and one with the amines cis (eq-eq) and the others trans. Can I also then put an amine axial with chlorine and another amine being equitorial and the H20 as the other axial, or is that repetitive? I've always had trouble telling what's redundant and what's not...

Ok, I see that better now. I wasn't accounting for the other ligands

Bidentate ligands can only bind in cis positions. I have trouble picturing 3d molecules in my head, but I'm counting 8 possible ways? I could be way off

My bad, I saw d5 and thought 5 bonds, even though I know there are 6. So it's octahedral.

It's d5, so it's either trigonal bipyramidal or square pyramidal. I'm going to go with trigonal bipyramidal because of the charge on the complex?

I'm struggling majorly with a problem. The directions are to draw all possible isomers for [Ru(bpy)(NH3)2(H2O)Cl]+. I'm struggling with drawing the structure of the compound itself, let alone the isomers. I know bpy is a bidentate ligand, but I'm not sure I'm clear on how that effects the structure. Thanks for any guidance!