vignesh3790

Let the number of animals with hari, jaggu and dinanath be x,y, and z respectively.. Case I : Hari gives six pigs to jaggu and gets one horse, then jaggu wil hav twice that of hari's. i.e., 2(X-6+1) = Y+6-1 => 2X-10 = Y+5 => 2X-Y= 15 ............. eqn (1) Case II :Dinanath gives fourteen sheeps to hari and gets one horse, then hari wil hav thrice that of dinanth's. i.e., 3(Z-14+1) = X+14-1 => 3Z-39 = X+13 => X-3Z = -52 ..............eqn(2) Case III: Jaggu gives four cows to dinanath and gets a horse, then dinanath wil have six times that of jaggu's. i.e., 6(Y-4+1) = Z+4-1 => 6Y-18 = Z+3 => 6Y-Z= 21 ................eqn(3) solving 1 and 2, we get (1)X2=> 2X+Y= 15 (2) 2X-6Z= -104 (-) (+) (+) ............ -Y+6Z= 119 ................eqn (4) solving (3) and (4) (3)x 6=> 36Y- 6Z = 126 (4)=> -Y+ 6Z = 119 .............. 35Y = 245 => Y=7 (jaggu) sub Y in eqn (1) 2X -7 =15 => 2X = 22 => X = 11 (hari) sub X in eqn (2) 11-3Z= -52 => -3Z= -63 => Z= 21 (dinanath)