Dear forum members
I am a biologist who is trying to synthesize an organic compound. I am trying to synthesize an organic compound 5-(2-hydroxy-5-nitrophenylazo)rhodanine using a protocol stated in article "Zaijun, L. et al. (2003). Analytical and Bioanalytical Chemistry 375, 408-413."
The protocol states that - Transfer 1.54 g of 4-nitro-2-aminophenol dissolved in 45 mL of 95% alcohol into a 100 mL beaker, add 12.0 mL of 6.0 mol L–1 HCI then cool the solution to 0 °C, and add 7 mL of 10% NaNO2 slowly. In another 200 mL beaker, 1.34 g of rhodanine and 14mL of 7.5 mol L–1 ammonia were added. After the solution has been cooled to 0 °C, add the above diazotized solution dropwise and leave the mixture overnight. The solution is then acidified to pH 1 with concentrated HCI and the precipitate was isolated and dried.
The crude product was re-crystallized from alcohol, giving pure 5-(2-hydroxy-5-nitrophenylazo)rhodanine (HNAR) in 65% yield.
When I acidify the reaction mixture I get yellow precipitate which are not soluble in ethanol. But when NaOH solution is added to these ppt. they solubelize just fine. According to authors this compound has three dissociation constants and it appears yellow in acidic conditions and red in basic conditions. As the compound has three states of pKa (2.75, 6.88, 10.91) can I precipitate this compound by using alkaline conditions? Also how can I check the purity of the compound formed?
Also I figured that this synthesis is a two step process which involves diazotization of 2-amino-4-nitrophenol followed by its addition to the solution of rhodanine. Can incomplete/inefficient diazotization be a problem in this synthesis? Is water essential for diazotization? Can I take conc. HCl or higher concentration of Sodium Nitrite to increase the efficiency of diazotization reaction?
Thanks.