zuriel

You're most certainly correct - thanks for the help!

Hi everyone, I'm learning NMR at the moment and I understand it relatively well - but I have a problem with this spectrum here and it's been bugging me for so long. Can anyone possibly offer some explanantion to me ? The compound is 2-methylpropan-1-ol : As you can see, there are 4 "types" of proton - the 'OH' the 'CH2' the 'CH' and the two chemically equivalent 'CH3's We'd expect 4 proton resonance signals and this is the case, (see spectrum here) : http://www.sigmaaldr.../FNMR000946.PDF I understand the doublet for the CH3, the triplet for the 'CH2' and 'OH' (if OH coupling occurs) but I don't understand the clear SEPTET for the 'CH' - because I'd expect a nonet! Does anyone have any idea why this might be the case in this spectrum? Could it be something to do with J values? Could there be a spectrum error? Any help would be greatly appreciated with this - it's driving me crazy! lol