Chikis

This equation [math]\frac{3}{10}\times{y}[/math] is in terms of what? Is it in terms of x or y?

This is what I had wanted to post before I had a latex error: If 30% of y is equal to x, what, in terms of x, is 30% of 3y? 30% of y=[math]\frac{30}{100}\times{y}=\frac{3}{10}\times{y}[/math] [math]\to[/math] [math]\frac{3}{10}\times{y}=x[/math] 30% of 3y =[math]\frac{3}{10}\times3y[/math] What do I make of these?

If 30% of y is equal to x, what, in terms of x, is 30% of 3y? 30% of y=[math]\frac{30}{100}\times{y}=\frac{3}{10}\times{y}\\\longto\\\frac{3}{10}\times{y}=x\\30% of 3y=\frac{3}{10}\times3y[/math] What do I make of these?

Never mind, am cleared.

Could it also mean the total number of students offering all the subject.

Hello friends, I was tackling a word problem on venn diagrams, when I came across the question: How many students are offering at least one of Biology or Chemistry? Looking at the question above, I want to understand what the phrase student offering at least one of Biology or Chemistry means. Who could interpret that phrase?

I don't. I use a phone.

Is not easy for me. My phone can't do it.

A REPOST TO CORRECT WHAT IS NOT CORRECT I have looked it up. The scale factor for the areas of the triangle is 4: 25 Using the scale factor, the area of [math]\bigtriangleup XYZ[/math] = [math]\frac{25\times{24}}{4}[/math] = [math]150cm^2[/math] To get the area of the trapezium PQZY, I subtract: Area of PQZY = 150-24 = [math]126cm^2[/math] Oh no! I still have problems of this nature that showing diagrams is making it impossible for me to bring in for help.

How do I show the triangle symbol using latex? For example, I want to write triangle ABC. Thank you.

I have looked it up. The scale factor for the areas of the triangle is 4: 25 Using the scale factor, the area of [math]\triangleXYZ[/math] = [math]\frac{25\times{24}}{4}[/math] = [math]150cm^2[/math] To get the area of the trapezium PQZY, I subtract: Area of PQZY = 150-24 = [math]126cm^2[/math] Oh no! I still have problems of this nature that showing diagrams is making it impossible for me to bring in for help.

Yes and yes. You made it. How did you do it?

How I wish I could show this problem in drawing. This problem has to deal with the concept of similar triangle. In a diagram, PQ//YZ. PQ is parallel to YZ, |XP| = 2cm, |PY| = 3cm, |PQ|= 6cm and the area of triangle [math]XPQ = 24cm^2[/math] Calculate the area of trapezium PQZY. Let me describe the shape. We have a large triangle XYZ. The large triange XYZ overllaps a small triangle XPQ I was able to find YZ using PX/YX = PQ/YZ i.e 2/5 =6/YZ YZ = 30/2 = 15 cm My greatest problem now is how to find the lenght XQ of the small triangle XPQ using the area [math]24cm^2[/math] given. I find it hard because I can't figure out the height. Though am taking PQ as the base. Could XQ be the height? I don't think so. If you understand my problem could you please draw the shape so that I can confirm it. I have the diagram with me; is just that I don't have the means to show it.

What if it is with latex, how do I go about it?

No, not totally like that. It should be like this 2c-10= a+5c + 5 = a-5 c - 15 = 10 The minus (subtract) need not to be there. Any mathmatically oriented user that sees it, knows that minus/plus went on there. I think I know what to do, but my browser or device never allows me to do it.

How do I show the underline when am solving equations? Let say am solving simultaneuos equation using elimination and I want to show the underline which shows that there is subtraction or addition going on, how do I do that? For example, in 2c-10= a+5 c + 5 = a-5 c - 25 =10

How do I show the underline when am solving equations? Let say am solving simultaneuos equation using elimination and I want to show the underline which shows that there is subtraction or addition going on, how do I do that? For example, in 2c-10= a+5 c + 5 = a-5 c - 25 =10

I have reasoned deep and have got the right equations. The equations are c-5 = a+5 2(c-5) = a+5 [math]\to[/math] 2c-10= a+5 c + 5 = a-5 c - 25 =10 using elimination method we have c = 35 Chidi has N35. from c-5 = a+5 [math]\to[/math] a = c-5-5 = 35-10 therefore Ade has N25.

But is my equation correct?

Let's look at it this way: Asuming that if Chidi gives out N5 to Ade, Ade's pay would be the same as Chidi's pay c-5 = a+5 Let's consider the case, where if Chidi gives out N5 to Ade, Ade will now have two times what Chidi has. That gives us the equation: c-5 = 2(a+5) I believe the above equation is correct.

Which image are you talking about?

Use the lens formula to show that [math]f^2 = ab[/math]. [math]f^2[/math]= square of focal length. a = object distance. b = image distance. I need help please. The lens formular =[math]\frac{1}{f}=\frac{1}{a}+\frac{1}{b}[/math] How do I do that?

How do I show the rightarrow sign?

If Ade gives N5 out of what he has to Chidi, the two of them will have equal amount. If Chidi gives out N5 to Ade, Ade will have twice as much as Chidi. How much did each of them have initially? The two people involved are Ade a and Chidi c a - 5 = c + 5 The above equation, is from the first sentence of the question. I found it difficult deriving an equation from the second sentence. Let me try. If Chidi gives out N5 to Ade, he has c-5. Ade has 2c [math]\to[/math] a = 2c How do reason to get a good equation for the second second sentence?